I'm wondering if we can make a dynamic function to access the cell template (xib template) for dynamic like this:
func create_image(TemplateName:??? = TemplateCell) {
var cell = self.tableView.cellForRow(at: currindexpath as IndexPath) as! TemplateName
}
I want to pass the "TemplateName" with the name of class of UITableViewCell:
class template1: UITableViewCell {
}
so on that parameter I can pass any template cell that I made. Is that possible? Sorry if hard to explain.
In a word: no. Swift is not dynamic in the way that you would like. The only thing that can go after as! is an actual literal type name — not some sort of reference to a type that you would pass in a variable or parameter.
You could, as an alternative, dequeue the cell and then ask what type the cell is, thus casting down safely and explicitly:
let cell = // ... dequeue the cell as a UITableViewCell
if let cell = cell as? MyTableViewCell {
// here, cell is a MyTableViewCell now
}
Using a switch statement instead of if, you could do that for all your different cell subclasses.
I have done this in one my sample project: Here is the sample code-
func setCardLayoutAccordingToId(cell: UITableViewCell,layoutId:Int) -> UITableViewCell {
let cgRect: CGRect = cell.contentView.frame
var layoutView: Any = DefaultCardView(frame: cgRect)
switch layoutId {
case 1:
layoutView = DefaultCardView(frame:cgRect)
case 2:
layoutView = Template_1(frame:cgRect)
case 3:
layoutView = Template_2(frame:cgRect)
case 4:
layoutView = Template_3(frame:cgRect)
default:
layoutView = DefaultCardView(frame:cgRect)
(layoutView as! DefaultCardView).setData(cardData: data)
}
for view in (cell.contentView.subviews)!{
view.removeFromSuperview()
}
cell.contentView.viewWithTag(1)?.addSubview(layoutView as! UIView)
(layoutView as! UIView).translatesAutoresizingMaskIntoConstraints = false
let attributes: [NSLayoutAttribute] = [.top, .bottom, .right, .left]
NSLayoutConstraint.activate(attributes.map {
NSLayoutConstraint(item: (layoutView as! UIView), attribute: $0, relatedBy: .equal, toItem: (layoutView as! UIView).superview, attribute: $0, multiplier: 1, constant: 0)})
return cell }
P.S: layout_Id can be decided as per your need.
You can pass the TemplateCell in a function indeed. For example:
func yourMethodForCell(_ cell: TemplateCell){
cell.backgroundColor = .red
}
Then call as follows:
yourMethodForCell(cell)
