Replace node in XML in XSLT

Question

I want to replace below node

 <Test>
        <Test.1>1</Test.1>
        <Test.2>ABC</Test.2>
        <Test.3>XXX</Test.3>
   </Test>

So If my input XML has Test node then "Test" node-name should be replace with node name as "aaa" Output should be like:

<aaa>
            <aaa.1>1</aaa.1>
            <aaa.2>ABC</aaa.2>
            <aaa.3>XXX</aaa.3>
 </aaa>

I have tried like:

 <xsl:when test="../name()='Test'">
     <aaa>
        <aaa.1>1</aaa.1>
        <aaa.2>ABC</aaa.2>
        <aaa.3>XXX</aaa.3>             
     </aaa>       

   </xsl:when>

Daniel Haley · Accepted Answer · 2018-01-17 16:53:03Z

3

You could use substring-after() to get the rest of the name and create the new one...

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output indent="yes"/>
  <xsl:strip-space elements="*"/>

  <xsl:template match="@*|node()">
    <xsl:copy>
      <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
  </xsl:template>

  <xsl:template match="*[starts-with(local-name(),'Test')]">
    <xsl:element name="aaa{substring-after(local-name(),'Test')}">
      <xsl:apply-templates select="@*|node()"/>
    </xsl:element>
  </xsl:template>

</xsl:stylesheet>

answered Jan 17, 2018 at 16:53

Daniel Haley

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Comments

Valdi_Bo · Accepted Answer · 2018-01-17 17:10:40Z

As I see, you want to change node name starting with Test, replacing Test with aaa.

To perform this task you need a template matching elements, which names start with Test. It can be made using a predicate in match attribute:

match="*[starts-with(name(), 'Test')]"

The content of this template should include:

Create a new element, with changed name (aaa + the "rest" of the tag name).
Apply templates to the content of the current element, like in the identity template.
Close the just created element.

Of course, the script should include also the identity template.

So the whole script can look like below:

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:transform version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="xml" encoding="UTF-8" indent="yes" />
  <xsl:strip-space elements="*"/>

  <xsl:template match="*[starts-with(name(), 'Test')]">
    <xsl:element name="aaa{substring(name(), 5)}">
      <xsl:apply-templates select="@*|node()"/>
    </xsl:element>
  </xsl:template>

  <xsl:template match="@*|node()">
    <xsl:copy><xsl:apply-templates select="@*|node()"/></xsl:copy>
  </xsl:template>
</xsl:transform>

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