PHP preg_replace with multiple variables

Question

I have the following short code I want to use to automatically generate Amazon Affiliate links in my posts [amazon region=com asin=xxxxxx].

How can I get the 'region' a and 'asin' from this string and convert every occurrence of it into my php function getAffiliateLink("com","xxxxxxxx")?

I can have multiple of these strings with different numbers on the page.

I have been looking into preg_replace and regex but I can't figure out how to do this for this particular example.

elaborate your expected result: should it be literally getAffiliateLink($region,$asin) or getAffiliateLink('com','xxxxxx') ? — RomanPerekhrest
– RomanPerekhrest, Commented Jan 22, 2018 at 22:08
When for example I put [amazon region=com asin=1234567] then I want this to be replaced in my code with getAffiliateLink("com","1234567"). There can be more links like these in one post with different asin numbers. ( I edited my question to make it more clear) — Senne Vandenputte
– Senne Vandenputte, Commented Jan 22, 2018 at 22:10
@revo I am completely new to preg_replace. I have looked into regex and regular expressions, but I have no idea how to implement that for this case. — Senne Vandenputte
– Senne Vandenputte, Commented Jan 22, 2018 at 22:17
Are region and asin always in the same order? or it can be different? — revo
– revo, Commented Jan 22, 2018 at 22:35

Senne Vandenputte · Accepted Answer · 2018-01-22 22:57:45Z

1

Ok so I found the solution. Because I want to replace the string with a function, I had to use preg_replace_callback().

This is my working solution:

$content = preg_replace_callback('/\[amazon region=([^\b]+) asin=([^\b]+)\]/', 'callback', $content);

function callback ($matches) {
    print_r($matches);
    return getAffiliateLink("$matches[1]","$matches[2]");
}

echo $content;

answered Jan 22, 2018 at 22:57

Senne Vandenputte

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