exception handling for undefined index error?

Question

The script below is called when saving my app's options page. All options are stored in an array in $options.

I'm getting a debug error "undefined index, id" on the line with the comment below. Any ideas how I can fix the script?

        foreach ($options as $value) 
        {
            if( isset( $value['id'] ) && isset( $_REQUEST[$value['id']] ) ) 
            {
                update_option( $value['id'], stripslashes($_REQUEST[$value['id']])  ); 
            }
            else
            {
                update_option( $value['id'], ""); //Error Here
            }
        }

rockerest · Accepted Answer · 2011-02-09 17:11:58Z

2

Your if{} segment precludes the code in your else{} segment from working.

In other words:

In your if block, you ask: "Does $value['id'] exist?"

If it does not, your code executes your else block, which then attempts to reference the non-existent variable.

You'll need to set the array key before you can update it.

Your update_option function should simply check to see if the variable exists, and set it instead of updating it, if it does not.

answered Feb 9, 2011 at 17:11

rockerest

10.5k3 gold badges39 silver badges67 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

Patrick Over a year ago

using this as a basis, the OP should think about updating update_option() to check if the array key exists before updating that key, and if the key != exist, create it first

rockerest Over a year ago

Hmm, that was my intention. I guess it wasn't clear. Thanks for clarifying.

Collectives™ on Stack Overflow

exception handling for undefined index error?

1 Answer 1

2 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

2 Comments

Your Answer

Sign up or log in

Post as a guest

Related