Python 3: Reading string from file and define the same string in code working differently [duplicate]

Question

I have a text file like below

    # 1.txt
    who is the\u00a0winners\u00a0where\u00a0season result\u00a0is 7th

If I read a file and print it, it shows

    >>> s = open("1.txt").read()
    >>> print(s)
    who is the\u00a0winners\u00a0where\u00a0season result\u00a0is 7th

However, If I do like below with the same string,

    >> s = "who is the\u00a0winners\u00a0where\u00a0season result\u00a0is 7th"
    >> print(s)
    who is the winners where season result is 7th

I want to read a text file like "1.txt" and print it like the below one. I can not find how to do it. Please help me. Thanks.

\u.... in string literals are being interpreted, read from text files they're not. — deceze
– deceze ♦, Commented Apr 9, 2018 at 8:11
Seems to have been discussed already before. Please have a look at : stackoverflow.com/questions/2594810/… — Kenstars
– Kenstars, Commented Apr 9, 2018 at 8:18
@deceze, Thanks for your comment. Is there a way to handle \u... in text file? — 이동준
– 이동준, Commented Apr 9, 2018 at 8:32

remi · Accepted Answer · 2018-04-09 08:10:56Z

0

\u00a0 is a non break space and is one character.

In your first example your are reading \u00a0 as 6 chars.

If you want to read a file with \u00a0s and interpret them as spaces, you would have to parse the file yourself and create spaces for each \u00a0.

answered Apr 9, 2018 at 8:10

remi

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2 Comments

이동준 Over a year ago

Thank you for your answer. However, I have several more unicodes. \u20132, \u20136, \u00e4 etc. Should I parse every \u things to read it? Thanks.

remi Over a year ago

If you look at the question in the answer of @Kenstars, one answer to that question is stackoverflow.com/a/2594942/4572356 . It is maybe the easiest way to do what you want to accomplish. Essentially using .replace on the string to replace a \u... with what it's definition is.

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