Array returns only last variable

Question

I am a newbe so maybe stupid question.. I have a couple of variables:

$opleidingscode1            = rgar( $entry, '31'); //$Opleidingssoortcode
$opleidingscode2            = rgar( $entry, '32'); //$Opleidingssoortcode
$opleidingscode3            = rgar( $entry, '33'); //$Opleidingssoortcode
$opleidingscode4            = rgar( $entry, '34'); //$Opleidingssoortcode
$opleidingscode5            = rgar( $entry, '35'); //$Opleidingssoortcode

Then put them in an array:

 $array = array( $opleidingscode1,$opleidingscode2,$opleidingscode3,$opleidingscode4,$opleidingscode5 );

Because only one variable has a value, rest is empty, i want to return only the value. So now i have:

$arrlength = count($array);

$string = "";
for($x = 0; $x < $arrlength; $x++) {
$string = $array[$x];
break; }

But it only returns a value if the last variable of the array has a value ($opleidingscode5)

What am i doing wrong?

Arthur · Accepted Answer · 2018-04-10 16:37:28Z

1

What you are doing here is a for-loop, that loops on each value of your array (you got that right), but it stores the last value of your table to your $string variable because that's what you asked it to do.

You may want to add a condition to your $string = $array[$x]; statement in order to check if its empty or not, since you said "Because only one variable has a value, rest is empty, i want to return only the value."

answered Apr 10, 2018 at 16:37

Arthur

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Yserbius · Accepted Answer · 2018-04-10 16:37:27Z

1

You're not checking if there's a value in the string, you're just getting each value and returning the last one. You need an if statement in your loop.

for($x = 0; $x < $arrlength; $x++) {
    if($array[$x] != NULL){
        $string = $array[$x];
    }
}

answered Apr 10, 2018 at 16:37

Yserbius

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Sebastian Sulinski · Accepted Answer · 2018-04-10 16:48:18Z

0

Here's what I would do - first filter for empty and then shift first item from the returned result:

$array = array_filter($array, function($value) {
    return !empty($value);
});

$value = array_shift($array);

That is if you only want the first item's value - otherwise you will already have all items that have values associated in the $array after running it via array_filter.

answered Apr 10, 2018 at 16:48

Sebastian Sulinski

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1 Comment

mickmackusa Dec 18, 2024 at 4:57

function($value) { return !empty($value); } is the default behaviour of array_filter() ... you can safely omit that part.

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