I am trying to combine multiple commands into a single output.
#!/bin/bash
x=$(date +%Y)
x=$($x date +m%)
echo "$x"
This returns
./test.sh: line 4: 2011: command not found
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6 Answers
x=$(echo $(date +%Y) $(date +%m))
(Note that you've transposed the characters % and m in the month format.)
2 Comments
John Bartholomew
There's no point using echo like that -- it doesn't add anything since you're just giving it a string and then capturing that same string again. You can just do
x="$(date +%Y) $(date +%m)"
rlibby
@John Bartholomew, you're right, it's a habit because I tend immediately to pipe echo to sed, etc.
In the second line, you're trying to execute $x date +m%. At this point, $x will be set to the year, 2011. So now it's trying to run this command:
2011 date +%m
Which is not what you want.
You could either do this:
x=$(date +%Y)
y=$(date +%m)
echo "$x $y"
Or that:
x=$(date +%Y)
x="$x $(date +%m)"
echo "$x"
Or simply use the final date format straight away:
x=$(date "+%Y %m")
echo $x
1 Comment
John Bartholomew
You have a typo/copy-paste error: you're still using
$y in your second example.Maybe this?
#!/bin/bash
x=$(date +%Y)
x="$x$(date +%m)"
echo "$x"
...also correcting what appears to be a transpose in the format string you passed to date the second time around.
Comments
Semicolon to separate commands on the command line.
date +%Y ; date +m%
Or if you only want to run the second command if the first one succeeds, use double ampersand:
date +%Y && date +%m
Or if you want to run both commands simultaneously, mixing their output unpredictably (probably not what you want, but I thought I'd be thorough), use a single ampersand:
date +%Y & date +%m
Comments
echo ´date +%Y´ ´date +m%´
Note the reverse accent (´)
2 Comments
Dennis Williamson
Except that you're using the wrong character. And
$() is preferred.
Alberto
Thanks, while I answer the question I was on Windows.
echo `date +%Y` `date +%m`
And to make the minimum change to the OP:
x=$(date +%Y)
x="$x $(date +%m)"
echo "$x"
