Combine output of two command in unix system

Question

I need to combine output of two commands.

For example:

If I input ls -l && file * it will give me

-rw-rw-r-- 1 user user 1356 2012-01-21 07:45 string.c
-rwxrwxr-x 1 user user 7298 2012-01-21 07:32 string_out
-rw-rw-r-- 1 user user  777 2012-01-18 21:44 test

string.c:   ASCII C program text, with CRLF line terminators
string_out: ELF 32-bit LSB executable, Intel 80386, version 1 (SYSV), dynamically linked (uses shared libs), for GNU/Linux 2.6.15, not stripped
test:       POSIX shell script text executable

but what I want is:

-rw-rw-r-- 1 user user 1356 2012-01-21 07:45 string.c string.c:   ASCII C program text, with CRLF line terminators
-rwxrwxr-x 1 user user 7298 2012-01-21 07:32 string_out string_out: ELF 32-bit LSB executable, Intel 80386, version 1 (SYSV), dynamically linked (uses shared libs), for GNU/Linux 2.6.15, not stripped
-rw-rw-r-- 1 user user  777 2012-01-18 21:44 test test:       POSIX shell script text executable

Any suggestions how to do this?

Janusz · Accepted Answer · 2017-08-08 10:11:12Z

7

Shiplu has a nice simple solution, in bash you can do it without using variables:

for x in *; do 
  echo "$(ls -dl $x) $(file $x)"
done;

Or:

for x in *; do echo "$(ls -dl $x) $(file $x)"; done;

In bash, $(cmd) takes the output of cmd and places it onto the command line, which is very useful for situations like this.

The $() form can be less error prone than using backticks (`cmd`) because it nests safely:

echo $(ls -l $(which bash))

With backticks you have to multiply escape things like quotes

edited Aug 8, 2017 at 10:11

Janusz

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answered Jan 21, 2012 at 21:49

Kyle Burton

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2 Comments

jaypal singh Over a year ago

Nicely done sir! +1, With while loop : while read list && read type <&3; do echo "$list $type"; done < <(tail +2 <(ls -l)) 3< <(file *) though a little cryptic. :)

Shiplu Mokaddim Over a year ago

@JaypalSingh why not you put this as an answer?

glenn jackman · Accepted Answer · 2012-01-23 14:18:44Z

5

paste is your friend here. Using bash process substitution:

paste <(ls -l | sed 1d) <(file *)

edit: added sed command to delete first line of ls output ("total: xx")

edited Jan 23, 2012 at 14:18

answered Jan 22, 2012 at 14:13

glenn jackman

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3 Comments

jaypal singh Over a year ago

I like this solution however, since ls -l shows total as the first row, the alignment becomes off i.e first line of output from file * gets displayed next to total.

glenn jackman Over a year ago

@jaypal, right but I wouldn't go crazy nesting process substitutions, it really harms readability.

evanb Over a year ago

You don't have to use another layer of process substitution, you can do paste <(ls -l | tail -n +2 ) <(file *) instead

Greg Hewgill · Accepted Answer · 2012-01-21 19:18:57Z

1

You can use the join command for this, but it might be tricky to do it all in one command line. If you create two files with the output of each command, it's pretty straightforward. You may need to massage the output a bit (such as removing the trailing : in the output of file).

answered Jan 21, 2012 at 19:18

Greg Hewgill

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Comments

Shiplu Mokaddim · Accepted Answer · 2012-01-21 19:32:04Z

1

You need a loop

 for x in *; 
 do 
      ls=`ls -dl $x`
      c=`file $x`
      echo "$ls $c"
 done;

In my Cygwin there is no file command. So I did it with wc. Their output format is almost same.

$ for x in *; do ls=`ls -l $x`; c=`wc -c $x`; echo "$ls : $c"; done;
-rwxr-xr-x 1 shiplu None 18460 Dec 23 16:27 a.exe : 18460 a.exe
-rw-r--r-- 1 shiplu None 340 Dec 23 16:27 tok.c : 340 tok.c

edited Jan 21, 2012 at 19:32

answered Jan 21, 2012 at 19:25

Shiplu Mokaddim

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2 Comments

glenn jackman Over a year ago

file is available for cygwin, you just have to install it using setup.exe

Shiplu Mokaddim Over a year ago

Thanks for letting me know. In fact I lost my setup.exe. :(

jaypal singh · Accepted Answer · 2012-01-22 04:48:24Z

1

Using `awk`:

awk '
NR==FNR{a[$9":"]=$0;next} 
($1 in a){printf("%-60s\t%-s\n",a[$1],$0)}' <(ls -l) <(file *)

Using `while` loop (Similar to @Shiplu and @Kyle's answer but using `while loop` with `field descriptors`:

while read list && read type <&3; do 
   echo "$list $type"; 
done < <(tail +2 <(ls -l)) 3< <(file *)

edited Jan 22, 2012 at 4:48

answered Jan 21, 2012 at 19:42

jaypal singh

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