Run remote Python script via curl

Question

I have a Python file where I can just run like this locally

script.py --ip=172.19.242.32 --mac=102030405060

Now I upload the script to my VM IP: 45.55.88.55.

How can I call the script via cURL and pass in proper flags?

I've tried

curl 45.55.88.55/script.py  | python --ip=172.19.242.32 --mac=102030405060

and

curl 45.55.88.55/script.py --ip=172.19.242.32 --mac=102030405060  | python

Both are not working. How can I debug this further?

Is there a way to prevent ssh ? I can share script with my team but not access into my VM. I’m trying to create a separation — code-8
– code-8, Commented Apr 18, 2018 at 16:35
Are you trying to store the script on the server, but run it locally? Or do you want to run the script on the server as well? — Barmar
– Barmar, Commented Apr 18, 2018 at 16:39
I want to store the script a Remote VM so I can run from other VMs or even locally. — code-8
– code-8, Commented Apr 18, 2018 at 16:41

Barmar · Accepted Answer · 2018-04-18 16:42:56Z

1

Arguments come after the script name. To use standard input as the script, use - as the name:

curl 45.55.88.55/script.py  | python - --ip=172.19.242.32 --mac=102030405060

This is a pretty standard Unix argument convention, although not all programs obey it (mostly older programs).

answered Apr 18, 2018 at 16:42

Barmar

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antzshrek · Accepted Answer · 2018-04-18 17:17:14Z

1

As @Barmar rightly said, Instead of running

curl 45.55.88.55/script.py  | python --ip=172.19.242.32 --mac=102030405060

which will make you miss your argument that is most times needed after whatever script name you're running. Which implies that you will need the short- delimiter character as the name

answered Apr 18, 2018 at 17:17

antzshrek

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