PHP foreach loop: loop one more time after certain condition is matched

Question

I am working with laravel and trying to get value of an array after another value using foreach loop. I am wondering what would be the best practice in solving this problem. So far I have tried this

$problems = $request->session()->get('problems');
$i = 0;
foreach ($problems as $prob) {
   $problem = $prob;
   if($request->problem_id == $prob->id){
         return 'Matched';
         die(); 
    }  
    $i++;  
}

so in an array of like [1,2,3,4] if you have the value 3 you want the 4th element? — Sérgio Reis
– Sérgio Reis, Commented Apr 19, 2018 at 8:46
Side note: You can remove the die();. Since you have a return before it, it will never get triggered. — M. Eriksson
– M. Eriksson, Commented Apr 19, 2018 at 8:47

Lucarnosky · Accepted Answer · 2018-04-19 08:50:59Z

4

Change your foreach in something like that

$shouldQuit = false;
foreach ($problems as $prob) {
   $problem = $prob;
   if($shouldQuit)
       break;
   if($request->problem_id == $prob->id){
         $shouldQuit = true;
   }  
}

edited Apr 19, 2018 at 8:50

answered Apr 19, 2018 at 8:47

Lucarnosky

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3 Comments

Nooglers BIT Over a year ago

Thanks, Exactly what I was looking for!

Lucarnosky Over a year ago

@NooglersBIT Glad to hear that, don't forget to mark this at the answer.

killstreet Over a year ago

You should probably just return or break inside the if statement, right now it will continue one more loop after a match was made.

Community · Accepted Answer · 2020-06-20 09:12:55Z

1

Eventhough @Lucarnosky code will work theres a faster way of handling this.

$problems = array_flip($request->session()->get('problems'));
if(key_exists($request->problem_id, $problems) return 'matched';
return 'problem not found';

php key_exists function

php array_flip function

edited Jun 20, 2020 at 9:12

CommunityBot

11 silver badge

answered Apr 19, 2018 at 11:03

killstreet

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