Adding array object to an array in a foreach loop if a condition is satisfied in php

Question

I have an array like this.

$array = [
       0 =>[
           "name" => "John",
           "age" => "20",
           "class" => "first"
       ],
       1 => [
           "name" => "Doe",
            "age" => "22",
            "class" => "second"
       ],
       2 => [
            "name" => "Template",
            "age" => "30",
            "class" => "third"
        ],
    ];

foreach ($array as $arr) {
    if ($arr["name"] == "Template") {
        $arr["result"] = ["maths" => "60", "English" => "20"];
        array_push($arr,$arr["result"]);
    }
}

I have tried several things like using array_push($arr,$arr["result"]) but that still returns the array. How can i loop through it to return something like this.

    2 => [
        "name" => "Template",
        "age" => "30",
        "class" => "third",
        "result"=> ["maths" => "60", "English" => "20"],
    ],

Alex Howansky · Accepted Answer · 2019-11-25 14:28:50Z

5

You're very close, just change this one line:

foreach ($array as $arr) {

To this:

foreach ($array as &$arr) {

And then remove the array_push(), as it's not needed. In the former, $arr is a copy of the subarray that gets discarded at the end of the loop iteration. In the latter, $arr is a pointer to the original subarray, so changes are maintained. See PHP: References Explained for details.

answered Nov 25, 2019 at 14:28

Alex Howansky

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1 Comment

Julyano Felipe Over a year ago

other way is use foreach ($array as $key => $arr) and then change value using $array[$key]

Andreas · Accepted Answer · 2019-11-25 14:30:10Z

3

you need to make the loop by reference with &

foreach ($array as &$arr) {
    if ($arr["name"] == "Template") {
        $arr["result"] = ["maths" => "60", "English" => "20"];
    }
}

This results in var_dump($array);:

array(3) {
  [0]=>
  array(3) {
    ["name"]=>
    string(4) "John"
    ["age"]=>
    string(2) "20"
    ["class"]=>
    string(5) "first"
  }
  [1]=>
  array(3) {
    ["name"]=>
    string(3) "Doe"
    ["age"]=>
    string(2) "22"
    ["class"]=>
    string(6) "second"
  }
  [2]=>
  &array(4) {
    ["name"]=>
    string(8) "Template"
    ["age"]=>
    string(2) "30"
    ["class"]=>
    string(5) "third"
    ["result"]=>
    array(2) {
      ["maths"]=>
      string(2) "60"
      ["English"]=>
      string(2) "20"
    }
  }
}

Another method is to make the array associative on name and directly access the correct subarray.

$array = array_column($array, null, "name");
$array["Template"]["result"] = ["maths" => "60", "English" => "20"];


var_dump($array);

https://3v4l.org/WFqfG

Just as with the loop method it requires unique names.

answered Nov 25, 2019 at 14:30

Andreas

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1 Comment

nellytadi Over a year ago

Thanks a lot. This was just what i needed.

user3532758 · Accepted Answer · 2019-11-25 14:49:46Z

2

Since there is a laravel tag, here is one way you could achieve it using laravel collections.

$array = collect($array)->map(function($item){
   if($item['name'] == "Template")
      $item['result'] = ["maths" => "60", "English" => "20"];
   return $item;
})->toArray();

collect method converts the array into a collection. map function will go over all elements of the array and using the callback function you can bring changes to the original collection. The changes are maintained. The toArray at the end is added assuming that the final data is required as an array. Without the, toArray it'd be a collection.

Edit: There was a laravel tag.

edited Nov 25, 2019 at 14:49

answered Nov 25, 2019 at 14:39

user3532758

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