1

How can I check if an array of strings contains part of words stored in another array of strings ?

Let's say I've declared these three arrays :

array1 = ["Lorem", "ipsum", "dolor" "sit" "amet"]

array2 = ["Lorem", "ipsum"]

keywords = ["ipsum", "dol"]

When comparing array1 with keywords, I want to get something like true because "ipsum" and "dol" are in array1, but false, when comparing array2 with keywords because "dol" isn't in array2

I searched for an hour, but I don't know how to do it... I succeeded to compare arrays with one keyword, but not with several keywords.

Improve this question
2
  • Should keywords be ["ipsum", "dolor"]? (dol -> dolor) Commented Apr 30, 2018 at 13:34
  • Keywords should be words like ipsum or part of words like just ipsu Commented Apr 30, 2018 at 13:38

5 Answers 5

Reset to default
4
  • For every element in keywords array (use .every())
  • There must be some element in other array (use .some())
  • That includes the string currently in consideration (use .includes())

Demo:

let array1   = ["Lorem", "ipsum", "dolor", "sit", "amet"],
    array2   = ["Lorem", "ipsum"],
    keywords = ["ipsum", "dol"];

let compare = (a, k) => k.every(s => a.some(v => v.includes(s)));

console.log(compare(array1, keywords));
console.log(compare(array2, keywords));

Docs:

Improve this answer
Sign up to request clarification or add additional context in comments.

3 Comments

Do you need the some?
@AndrewBone yes, without some how we will find a match between keyword item and any element in other array?
Thank you @MohammadUsman, it helps me a lot !!! I try to do it before asking the question, but I use 2 loops and it wasn't really clean ^^
3

You can use Array.every

let contains = keywords.every(k => array1.findIndex(a => a.indexOf(k) > -1) > -1)
Improve this answer

Comments

0 
function arrayContains(array1,array2){
 var res=0;
 for (var i=0;i<array1.length;i++){
  for (var j=0;i<array2.length;j++){
    if (array1[i]==array2[j])
        res++
   } 
 }
 return res==array2.length//if res is eqaul to array2.length then all elements of array2 are inside array1;
}
Improve this answer

Comments

0

I would use indexOf instead of includes as includes do not work in IE browsers. Browser compatibility

let array1   = ["Lorem", "ipsum", "dolor", "sit", "amet"],
    array2   = ["Lorem", "ipsum"],
    keywords = ["ipsum", "dol"];

let compare = (a, k) => k.every(s => a.some(v => v.indexOf(s) !== -1));

console.log(compare(array1, keywords));
console.log(compare(array2, keywords));

Improve this answer

2 Comments

Thank you for the tip ;)
If not mistaken, arrow functions do not work in IE browsers as well.
-1 
var array1 = ['a','b','c'];
var array2 = ['g','f','h'];

var keys = ['a','g'];

function checkIfExists(key, arr) {
   if (arr.indexOf(key) != -1) {
     console.log('Key ' + key + ' exists in array');
   } else {
     console.log('Key ' + key + ' does not exists in array');
   } 

}

for (var i = 0; i < keys.length; i++) {
    checkIfExists(keys[i], array1);
}

for (var i = 0; i < keys.length; i++) {
    checkIfExists(keys[i], array2);
}

Output :

Key a exists in array Key g does not exists in array Key a does not exists in array Key g exists in array

Improve this answer

1 Comment

I wrote keywords.every(k => array1.indexOf(k) > -1), but it works only when the keyword is the full word, i want to have also part of word

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.