Check value is equal to specific value in an array - javascript

Question

I have the below object

members
    {
        [
            age:30,
            list: [
                "PRICE",
                "LIST",
                "COUNTRY"
            ]
        ]
    },
    {
        [
            age:31,
            list: [
                "PRICE"
            ]
        ]
    },
    {
        [
            age:31,
            list: [
                "LIST"
            ]
        ]
    }

I need to check if array values are equal to specific value.

I need to check if list has PRICE or list has COUNTRY or list has PRICE,LIST,COUNTRY combination.

Currently I'm using includes which checks if value is present. But i need to check exact value

Array.isArray(members.list.map(message, index){
        if(message.includes("LIST"))
        {

        }
        if(message.includes("PRICE"))
        {

        }
         if(message.includes("PRICE") && message.includes("LIST") && message.includes("COUNTRY"))
        {
            //message.includes("PRICE") and ("LIST") is already executed, so this will execute again. But i need to execute the complete condition combination.
        }
    })

How to acheive this?

Array.isArray(members.list.map(...)) makes not that much sense as .map() will always return an array O.o — Andreas
– Andreas, Commented May 3, 2018 at 9:32
Turn the comparison to have the most specific first, then use else: if(message.includes("PRICE") && message.includes("LIST") && message.includes("COUNTRY")) {} else if(message.includes("LIST")) {} else if(message.includes("PRICE")) { } — mplungjan
– mplungjan, Commented May 3, 2018 at 9:35
@siraxtas but that post does not show about checking combination — Matarishvan
– Matarishvan, Commented May 3, 2018 at 9:37

Sam Ho · Accepted Answer · 2018-05-03 09:58:58Z

0

Your concern is to loop through all possible if condition.
So you shouldn't do return within a condition checking.
You can save the result and override it whenever it matches a condition. Hope can help.
Also there is some problem of your origin members Object. Also fixed in the following demo.

let members = [
	{ age: 30, list: ["PRICE", "LIST", "COUNTRY"] },
	{ age: 31, list: ["PRICE"] },
	{ age: 31, list: ["LIST"] }
];

   Array.prototype.inArray = function () {
var message = this;
if (message.includes("PRICE") && message.includes("LIST") && message.includes("COUNTRY")) {
	return "contains PRICE, LIST and COUNTRY";
}
if (message.includes("PRICE") && message.includes("LIST") ) {
	return "contains PRICE and LIST ";
}
if (message.includes("PRICE") &&  message.includes("COUNTRY")) {
	return "contains PRICE and COUNTRY";
}
if (message.includes("LIST") && message.includes("COUNTRY")) {
	return "contains LIST and COUNTRY";
}
if (message.includes("LIST")) {
	return "contains LIST";
}
if (message.includes("PRICE")) {
	return "contains PRICE";
}
if (message.includes("LIST")) {
	return "contains LIST";
}
}

for (let member of members) {
	console.log(member.list.inArray());
}

edited May 3, 2018 at 9:58

answered May 3, 2018 at 9:50

Sam Ho

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2 Comments

Matarishvan Over a year ago

I want either PRICE or PRICE, LIST, COUNTRY combination to execute.. In your code, both will execute

Sam Ho Over a year ago

Sorry that i have misunderstand your question. The most stupid solution are as the edited answer.

Pavan Sikarwar · Accepted Answer · 2018-05-03 10:16:33Z

0

Hope this will help

var members = [
	{ age: 30, list: ["PRICE", "LIST", "COUNTRY"] },
	{ age: 31, list: ["PRICE"] },
	{ age: 31, list: ["LIST"] }
];
members.forEach((val,key)=>{
	if(Array.isArray(val.list)){
		if(val.list.indexOf('PRICE') > -1 || val.list.indexOf('COUNTRY') > -1 || (val.list.indexOf('PRICE') > -1 && val.list.indexOf('COUNTRY') > -1 && val.list.indexOf('LIST') > -1)){
			console.log(val)
		}
	}
});

edited May 3, 2018 at 10:16

answered May 3, 2018 at 10:09

Pavan Sikarwar

8086 silver badges14 bronze badges

Comments

HMR · Accepted Answer · 2018-05-03 10:26:44Z

You can compose a filter function and use that for Array.prototype.filter

const members = [
  {
    age: 30,
    list: ["PRICE","LIST","COUNTRY"]
  },
  {
    age: 31,
    list: ["PRICE"]
  },
  {
    age: 31,
    list: ["LIST"]
  },
  {
    age: 88,
    list: ["not this one"]
  },
  {
    age: 88,
    list: ["not this one","COUNTRY","NOTPRICEORLIST"]
  }
]

const getList = o => (o&&o.list) || [];//get list member from o or returns empty array
const contains = needle => haystack => haystack.includes(needle);//check if haystack contains needle
const containsAll = needles => haystack => needles.reduce(
  (result,needle)=>result && haystack.includes(needle),
  true
);
const countryOrPriceOrPriceListCountry = haystack =>
  contains("PRICE")(haystack) || contains("LIST")(haystack)
  //this is pointless, would already be true because it contains price or country
  // || containsAll(["PRICE","LIST","COUNTRY"])(haystack);

const filter = getter => comparer => item =>//get something from item (list) and send to compare function
  comparer(getter(item));

console.log(
  members.filter(filter(getList)(countryOrPriceOrPriceListCountry))
);

Or maybe you were looking for the following:

const members = [
  {
    age: 30,
    list: ["PRICE","LIST","COUNTRY"]
  },
  {
    age: 31,
    list: ["PRICE"]
  },
  {
    age: 32,
    list: ["LIST"]
  },
  {
    age: 88,
    list: ["not this one"]
  },
  {
    age: 89,
    list: ["not this one","COUNTRY","NOTPRICEORLIST"]
  }
]

const getList = o => (o&&o.list) || [];//get list member from o or returns empty array
const contains = needle => haystack => haystack.includes(needle);//check if haystack contains needle
const containsAll = needles => haystack => needles.reduce(
  (result,needle)=>result && haystack.includes(needle),
  true
);
const countryOrPrice = haystack =>
  contains("PRICE")(haystack) || contains("LIST")(haystack)
const countryListAndPrice = containsAll(["PRICE","LIST","COUNTRY"]);

members.map(
  item=>[item,countryOrPrice(getList(item))]//see if item has country or price
).map(
  ([item,hasCountryOrPrice])=>[
    item,
    hasCountryOrPrice,
    // will check for country list and price only if has country or price 
    hasCountryOrPrice && countryListAndPrice(getList(item))
  ]
).forEach(
  ([item,hasCountryOrPrice,countryListAndPrice])=>
    console.log(
      "item age:",
      item.age,
      "has country or price:",
      hasCountryOrPrice,
      "has country list and price:",
      countryListAndPrice
    )
);

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