Curl command in Python 3

Question

I want to execute a curl with command in python.

Usually, I just need enter the command in terminal and press return key.

The command shows below:

curl -H "`oauth2l header --json key.json mobileinsights`"  https://mobileinsights.googleapis.com/v2/networks

The result is in json format.

Possible duplicate of how to use python to execute a curl command — FabienP
– FabienP, Commented May 9, 2018 at 20:35
You could use subprocess to run oauth2l header --json key.json mobileinsights from Python... Then use whatever HTTP library in python to pass a header — OneCricketeer
– OneCricketeer, Commented May 9, 2018 at 20:39

Wesley Smith · Accepted Answer · 2018-05-09 20:53:47Z

1

Use the subprocess module to run your shell command.

import subprocess
result = subprocess.check_output('curl -H "`oauth2l header --json 
key.json mobileinsights`" https://mobileinsights.googleapis.com/v2/networks', shell=True)

Then, use the json module to parse the JSON data returned by the server.

import json
result_json = json.loads(result)

answered May 9, 2018 at 20:53

Wesley Smith

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AliRazaRizwe · Accepted Answer · 2018-05-09 20:42:44Z

0

You may load an OS and JSON load modules and then run os.execute(curl URL) store it in any variable then convert it into JSON format with JSON load module

answered May 9, 2018 at 20:42

AliRazaRizwe

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