Filtering an array with objects with another array with strings

Question

I have 2 arrays and I want to filter one of the arrays with another array.

2 arrays designed like this

array1= [{id:23},{id:11},{id:435}]

array2= [23, 435, 5]

I want to check and get items only if id of objects inside array1 is equal to one of the ids (string values ) in array2

I found a simple solution like this

var filtered=[1,2,3,4].filter(function(e){return this.indexOf(e)<0;},[2,4]);

but my case is a bit different, I dont know how to make return part, how can I get indexes of each array ?

var filtered=array1.filter(function(e){return e.id === ??},array2);

please add the wanted result. why do you need to use this? — Nina Scholz
– Nina Scholz, Commented May 16, 2018 at 18:06
This answer explains about filtering. Look for more complex comparer — HMR
– HMR, Commented May 16, 2018 at 18:17

Nina Scholz · Accepted Answer · 2018-05-16 19:12:50Z

1

You could just look up the index by using the id property.

var array1 = [{ id: 23 }, { id: 11 }, { id: 435 }],
    array2 = [23, 435, 5],
    filtered = array1.filter(function (o) {
        return array2.indexOf(o.id) > -1;
    });
    
console.log(filtered);

ES6

var array1 = [{ id: 23 }, { id: 11 }, { id: 435 }],
    array2 = [23, 435, 5],
    filtered = array1.filter(({ id }) => array2.includes(id));
    
console.log(filtered);

edited May 16, 2018 at 19:12

answered May 16, 2018 at 18:08

Nina Scholz

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1 Comment

Rasim Avcı Over a year ago

thanks but it only worked when I make it > -1 instead of < 0 I think you thought it reverse

Explosion Pills · Accepted Answer · 2018-05-16 18:08:08Z

0

You can use .filter and essentially check if the object id exists in array2. There are several ways to do that including .find and .findIndex. I would use .some which returns true if a single match is found.

array1.filter(obj => array2.some(id => id === obj.id));

answered May 16, 2018 at 18:08

Explosion Pills

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