Converting the string resources to strings

Question

I've already tried to use

String mystring = getResources().getString(R.string.mystring);

And I found the same theme in this article How can I convert the android resources int to a string. eg.: android.R.string.cancel?. But it doesn't work in my situation.

This is my code:

public class Film{


  private int image;
    private String name;
    private  String schedule;
    private  String description;

    public Film() {
    }

    public int getImage() {
        return image;
    }

    public void setImage(int image) {
        this.image = image;
    }

    public String getName() {
        return name;
    }
    public void setName(String name) {
        this.name = name;
    }
       ...
    public String getDescription() {
        return description;
    }
    public void setDescription(String description) {
        this.description = description;
    }
}

public class FilmList {


 public static   ArrayList<Film> getFilms(){
        ArrayList<Film>films=new ArrayList<>();
        Film film=null;

        film =new Film();
        film.setName(getResources().getString(R.string.name1));
        film.setImage(R.drawable.img1);
        film.setDescription(getResources().getString(R.string.desc1));
        films.add(film);

        film =new Film();
        film.setName(getResources().getString(R.string.name2));
        film.setImage(R.drawable.img2);
        film.setDescription(getResources().getString(R.string.desc2));
        films.add(film);

        return films
         }
    }

You can create resource instance in application class, and access it anywhere, because application class is live till your app is running. — Khemraj Sharma
– Khemraj Sharma, Commented May 21, 2018 at 17:18

Bryan Herbst · Accepted Answer · 2018-05-21 16:30:01Z

1

If you don't have access to a Context (e.g. via an Activity, Service, ContentProvider, or BroadcastReceiver), you cannot get a string resource.

If you have a class that is not one of the above and it needs to get a string resource, you must either have pass a Context to that class so it can retrieve the resource, or pass that class an already-resolved resource.

answered May 21, 2018 at 16:30

Bryan Herbst

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Comments

Suhaib Roomy · Accepted Answer · 2018-05-21 16:53:37Z

Make an application class and add a hold its reference in a static varialble. then you can access context anywhere in the app

public class MyApp extends Application {

    private static AppLWP instance;

    @Override
    public void onCreate() {
         super.onCreate();
         instance = this;
    }
 }

Then you can access this instance for context anywhere in the app

public static ArrayList<Film> getFilms(){
    ArrayList<Film>films=new ArrayList<>();
    Film film=null;

    film =new Film();
    film.setName(MyApp.instance.getResources()
    .getString(R.string.name1));
    film.setImage(R.drawable.img1);        
    film.setDescription(MyApp.instance.getResources()
    .getString(R.string.desc1));

    films.add(film);

    film =new Film();        
    film.setName(MyApp.instance.getResources()
    .getString(R.string.name2));
    film.setImage(R.drawable.img2);
    film.setDescription(MyApp.instance.getResources()
    .getString(R.string.desc2));
    films.add(film);

    return films
     }
}

Peter Stewart · Accepted Answer · 2018-05-21 17:04:12Z

0

First, provide context to the class Film via the activity you are calling the object of Film.

If you call from Main Activity you will have to do something like this:

public class MainActivty extends AppCompatActivity {

private static MainActivty obj;
onCreate() {
     //usual functions
     obj = MainActivity.this;
   }
}

Once you have the context, simply try this:

String mystring = context.getString(R.string.mystring);

Or, if you floowed my MainActivty method:

String mystring = MainActivty.obj.getResources().getString(R.string.mystring);

answered May 21, 2018 at 17:04

Peter Stewart

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