Android - retrieve string array from resources

Question

Below is the code that i made to retrieve the string array item:

String[] menuArray;

@Override
public void onCreate(Bundle savedInstanceState) 
{       
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    ScrollView sv = new ScrollView(this);
    LinearLayout ll = new LinearLayout(this);
    ll.setOrientation(LinearLayout.VERTICAL);
    sv.addView(ll);

 // Create an ArrayAdapter that will contain all list items
    ArrayAdapter<String> adapter;

    menuArray = getResources().getStringArray(R.array.menu); 


    for(int i = 0; i < menuArray.length; i++) 
    {
        Button b = new Button(this);
        b.setText(menuArray[i]);
        ll.addView(b);
    }

    this.setContentView(sv);
 }

This is the strings.xml file:

 <string-array name="menu">
        <item>1</item>
        <item>2</item>
        <item>3</item>
        </string-array>

However, the R.array.menu having this issue to compile: As of ADT 14, resource fields cannot be used as switch cases. Invoke this fix to get more information.

Yeah, i can provide you snapshot from emulator if you want to see. I just skipped the use of variable x along with try catch block as definition of count() is not provided. — Imran Rana
– Imran Rana, Commented May 10, 2012 at 12:02
i solve it d.. it is just because i move out the app_name from the strings.xml LOL — Yuen Tong
– Yuen Tong, Commented May 10, 2012 at 14:04

Suragch · Accepted Answer · 2017-08-28 07:24:39Z

94

How to retrieve a string array from resources:

array.xml

<?xml version="1.0" encoding="utf-8"?>
<resources>

    <string-array name="my_string_array">
        <item>one</item>
        <item>two</item>
        <item>three</item>
    </string-array>

</resources>

Code

String[] stringArray = getResources().getStringArray(R.array.my_string_array);

(The OP already had their question answered but based on the question title, other people may come here looking for this answer.)

answered Aug 28, 2017 at 7:24

Suragch

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Comments

c2dm · Accepted Answer · 2012-05-10 12:28:32Z

8

for(int i = 0;i<menuArray.length; i++) 
{
    Button b = new Button(this);
    b.setText(menuArray[i]);
    ll.addView(b);
}

Delete the below statement

 try {
        x = count();
    } catch (IOException e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
    }

and try to give layout height and width to all Layouts..

answered May 10, 2012 at 12:28

c2dm

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2 Comments

Yuen Tong Over a year ago

i have update the code above. But still having the same issue for the R.array.menu.

c2dm Over a year ago

Take a separate arrays.xml and take string array t<?xml version="1.0" encoding="utf-8"?> <resources> <array name="testArray"> <item>first</item> <item>second</item> <item>third</item> <item>fourth</item> <item>fifth</item> </array> </resources>here

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