search inside child Array of objects - JavaScript

Question

Currently i have below Array of Objects

obj = [
    {
        "id":28,
        cities: [
            {
                cityTypes: "AA",
                citySource: "sdsf"
            },
            {
                cityTypes: "BB",
                citySource: "sdsgf"
            },
            {
                cityTypes: "CC",
                citySource: "fgsdfgd"
            }
        ]
    }, 
    {
        "id":56,
        cities: [
            {
                cityTypes: "DD",
                citySource: "sdsf"
            },
            {
                cityTypes: "EE",
                citySource: "sdsgf"
            },
            {
                cityTypes: "FF",
                citySource: "fgsdfgd"
            }
        ]
    }, 
    {
        "id":89,
        cities: [
            {
                cityTypes: "GG",
                citySource: "sdsf"
            },
            {
                cityTypes: "HH",
                citySource: "sdsgf"
            },
            {
                cityTypes: "II",
                citySource: "fgsdfgd"
            }
        ]
    }
]

I need to search cityTypes of specific value is present in the whole Object.

For suppose, i need to search cityTypes = BB

If BB is present in the whole object, return true

If BB is not preset, return false.

This is what i have tried, which does not seem to work.

for(let k=0; k<obj.length; k++){
    if(obj[k].cities){
        let cityObj = obj[k].cities;
        for(let city in cityObj){
            city.cityTypes !== "BB" ? "true" : "false"
        }
    }
}

What is the proper way to achieive this?

CertainPerformance · Accepted Answer · 2018-09-07 07:07:08Z

1

You might use a .some inside another .some:

const obj=[{"id":28,cities:[{cityTypes:"AA",citySource:"sdsf"},{cityTypes:"BB",citySource:"sdsgf"},{cityTypes:"CC",citySource:"fgsdfgd"}]},{"id":56,cities:[{cityTypes:"DD",citySource:"sdsf"},{cityTypes:"EE",citySource:"sdsgf"},{cityTypes:"FF",citySource:"fgsdfgd"}]},{"id":89,cities:[{cityTypes:"GG",citySource:"sdsf"},{cityTypes:"HH",citySource:"sdsgf"},{cityTypes:"II",citySource:"fgsdfgd"}]}];

console.log(
  obj.some(({ cities }) => cities.some(({ cityTypes }) => cityTypes === 'BB'))
);
console.log(
  obj.some(({ cities }) => cities.some(({ cityTypes }) => cityTypes === 'foobar'))
);

answered Sep 7, 2018 at 7:07

CertainPerformance

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Comments

Ankit Agarwal · Accepted Answer · 2018-09-07 07:12:39Z

Your existing code do not work because of several reason:

You need to do let city of cityObj since you are accessing property of city as city.cityTypes inside the inner loop so using of will give you each object in city variable.
You need to actually check if the match is found or not using a if condition. If a match is found with the cityTypes you expect then break the inner loop. Also break the outer loop if the match is found.

var obj = [{
    "id": 28,
    cities: [{
        cityTypes: "AA",
        citySource: "sdsf"
      },
      {
        cityTypes: "BB",
        citySource: "sdsgf"
      },
      {
        cityTypes: "CC",
        citySource: "fgsdfgd"
      }
    ]
  },
  {
    "id": 56,
    cities: [{
        cityTypes: "DD",
        citySource: "sdsf"
      },
      {
        cityTypes: "EE",
        citySource: "sdsgf"
      },
      {
        cityTypes: "FF",
        citySource: "fgsdfgd"
      }
    ]
  },
  {
    "id": 89,
    cities: [{
        cityTypes: "GG",
        citySource: "sdsf"
      },
      {
        cityTypes: "HH",
        citySource: "sdsgf"
      },
      {
        cityTypes: "II",
        citySource: "fgsdfgd"
      }
    ]
  }
]
var found = false;
for (let k = 0; k < obj.length; k++) {
  if (obj[k].cities) {
    let cityObj = obj[k].cities;
    for (let city of cityObj) {
      found = city.cityTypes === "BB";
      if (found) {
        break;
      }
    }
  }
  if (found) {
    break;
  }
}
console.log(found);

Chris Li · Accepted Answer · 2018-09-07 07:13:48Z

Using a double reduce should work

var obj = [{
    "id": 28,
    cities: [{
        cityTypes: "AA",
        citySource: "sdsf"
      },
      {
        cityTypes: "BB",
        citySource: "sdsgf"
      },
      {
        cityTypes: "CC",
        citySource: "fgsdfgd"
      }
    ]
  },
  {
    "id": 56,
    cities: [{
        cityTypes: "DD",
        citySource: "sdsf"
      },
      {
        cityTypes: "EE",
        citySource: "sdsgf"
      },
      {
        cityTypes: "FF",
        citySource: "fgsdfgd"
      }
    ]
  },
  {
    "id": 89,
    cities: [{
        cityTypes: "GG",
        citySource: "sdsf"
      },
      {
        cityTypes: "HH",
        citySource: "sdsgf"
      },
      {
        cityTypes: "II",
        citySource: "fgsdfgd"
      }
    ]
  }
]
var cityTypes1 = 'BB';
console.log(obj.reduce((total, cur) => 
    total||cur.cities.reduce((total, cur) => 
        total||cur.cityTypes === cityTypes1, false), 
    false))

Pavel Lauko · Accepted Answer · 2018-09-07 07:24:37Z

0

This short method returns true if at least one of city has required type:

function findMyCode(code) {
   return obj.some((d) => {
       return d.cities.some((city) => {
           return city.cityTypes === code;
       });
   });
}

Or you can try use lodash library.

So you can use it:

var hasType = findMyCode('BB'); // returns true/false

answered Sep 7, 2018 at 7:24

Pavel Lauko

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Comments

Mayank Mishra · Accepted Answer · 2018-09-07 07:33:12Z

0

Give a try with below code.

var result = false;
for(let k=0; k<obj.length; k++){
    if(obj[k].cities){
        let cityObj = obj[k].cities;
        for(let city in cityObj){
            if(cityObj[city].cityTypes == "BB"){
                result = true;
            }
        }
    }
}

return result or print console log.

edited Sep 7, 2018 at 7:33

answered Sep 7, 2018 at 7:29

Mayank Mishra

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Comments

KhorneHoly · Accepted Answer · 2018-09-07 09:33:25Z

0

var filtered = obj.filter((o) => {
    var found=false;
    for(let i=0;  i<o.cities.length; i++) {
        let city = o.cities[i];
        if(city.cityTypes === "BB"){
            found=true;
            break;
        }
    }
    return found;
})
console.log(filtered)

edited Sep 7, 2018 at 9:33

KhorneHoly

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answered Sep 7, 2018 at 7:14

Mahesh Thumar

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