need a pattern to match a string which should NOT be --
777777777
888888888
999999999
or start with 00 or 02 or 04.
when i tried to go create a pattern to match the above requirements, i got it done by -
Dim _pattern6 As String = "^(7+|8+|9+|(00|07|08|09|17|18|19|28|29|43|48|69|70|78|79|80|96|97).*)$"
could not get the NOT MATCH part done.
What you want is negative lookahead.
@"^(?!([789])\1{8}$|0[024]).*$"
The negative lookahead (?!...) means "whatever follows this position cannot match any of these patterns." So (?!7{9}).* means "any string of characters (.*) that doesn't start with nine 7s in a row." The ([789])\1{8}$ is shorthand for 9 repeated digits. It means "Either 7, 8, or 9 followed by itself another 8 times."
Tested on RegexPlanet: http://fiddle.re/tz8p
$ 's at the end of a regex, does it work? (though I suppose you aren't matching it just looking at it the first time). So, +1 to you sir.
$ is just saying that whatever follows is going to be something other than 9 of the same number [7-9] and an end-of-line. $ is valid anywhere in a regex as long as the result still makes sense, so (^foo$|^bar$|^baz$) would work fine, whereas foo$bar$ wouldn't. Thanks for the +1. :)You could try to match to unwanted parts. If that returns true, you know the attempt to "not match" would have been false, and vice versa.
Here you go
[^(7{9}|8{9}|9{9}|00|02|04)]+
[^024789]+ ie "anything other then these numbers"
[^(7{9}|8{9}|9{9}|00|02|04)] is equivalent to [^024789(){}|], which matches any one character as long it's not one of those in the list.