PHP - Extract current directory and filename from file path

Question

I need to turn this:

/home/me/public_html/folder1/folder2/folder3/script.php

Into:

folder3/script.php

So far, I have tried using:

(\/.+\/.+\.php)$

However the end result is the entire path is returned. What am I doing wrong?

The dot . will also match the slash /. Change your regular expression to exclude the dot: (/[^/]+/[^/]+\.php)$. Also, use php.net/manual/function.dirname.php instead. — Corion
– Corion, Commented Oct 22, 2018 at 9:24

Rubin Porwal · Accepted Answer · 2018-10-22 09:32:30Z

3

$path='/home/me/public_html/folder1/folder2/folder3/script.php';
$pathinfo=pathinfo($path);
$a=explode(DIRECTORY_SEPARATOR,$pathinfo['dirname']);
$dir=end($a);
echo $dir.DIRECTORY_SEPARATOR.$pathinfo['basename'];

answered Oct 22, 2018 at 9:32

Rubin Porwal

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5 Comments

Mohammad Over a year ago

I think using explode('/'.. is simpler

coladict Over a year ago

Simpler, but not cross-platform.

Mohammad Over a year ago

@coladict For example ...?

coladict Over a year ago

@Mohammad Windows CLI.

Reado Over a year ago

Good job I'm using Linux then, as per the directory structure in the initial post!

sanjaya · Accepted Answer · 2018-10-22 10:01:11Z

0

<?php
$pathinfo=pathinfo('/home/me/public_html/folder1/folder2/folder3/script.php');
$a=explode('/',$pathinfo['dirname']);
echo $dir=end($a);
echo $pathinfo['basename'];
?>

answered Oct 22, 2018 at 10:01

sanjaya

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