Create table using only PHP from array of values

Question

I've to print a table using TCPDF for creating a PDF using PHP from an array of contents.

In my example I'll use 7 entries, but can be more or less.

$array = array(
 0 => "[ ] Option 1",
 1 => "[x] Option 2",
 2 => "[ ] Option 3",
 3 => "[ ] Option 4",
 4 => "[x] Option 5",
 5 => "[ ] Option 6",
 6 => "[ ] Option 7",
 ...
);

My table layout is dynamic: I can set numbers of columns for display purpose ( $num_cols can be 1, 2, 3 or 4 columns)

Based on my $num_cols, I've to split my content of the array in each TD cell.

So, if I set $num_cols = 4, i need to show something like that:

<table>
  <tr>
    <td>[ ] Option 1</td>
    <td>[x] Option 2</td>
    <td>[ ] Option 3</td>
    <td>[ ] Option 4</td>
  </tr>
  <tr>
    <td>[x] Option 5</td>
    <td>[ ] Option 6</td>
    <td>[ ] Option 7</td>
    <td></td>
  </tr>
</table>

I tried to start some ideas but in this example I can get only a row. I don't know how to create the external loop:

echo "<table>";
echo "<tr>";

for ( $i = 0; $i < $num_cols; $i++ ) {

 echo "<td>";
 if ( isset($array[$i]) {echo $array[$i];} else {}
 echo "</td>";

}
echo "</tr>";
echo "</table>";

Side note: you do not need empty else statements. You can get rid of your 'else {}'. — Kishlin
– Kishlin, Commented Oct 30, 2018 at 16:58

k0pernikus · Accepted Answer · 2018-10-30 17:14:20Z

4

array-chunk will help you:

<?php
$num_cols = 4;
$array = [1,2,3,4,5,6,7,8];

echo "<table>";
foreach (array_chunk($array, $num_cols) as $chunk) {
    echo "<tr>";
    foreach ($chunk as $item) {
        echo "<td>";
        echo $item;
        echo "</td>";
    }
    echo "</tr>";
}
echo "</table>";

and you can use some other cool-stuff from php :)

<?php
$num_cols = 4;
$array = [1,2,3,4,5,6,7,8];

echo "<table><tr><td>" .
    implode("</td></tr><tr><td>",
        array_map(function(array $part) {
            return implode('</td><td>', $part);
        }, array_chunk($array, $num_cols))
    )
. "</td></tr></table>";

edited Oct 30, 2018 at 17:14

k0pernikus

67.6k78 gold badges245 silver badges366 bronze badges

answered Oct 30, 2018 at 16:53

myxaxa

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Comments

Mic1780 · Accepted Answer · 2018-10-30 17:07:19Z

2

<?php
$array = array(
 0 => "[ ] Option 1",
 1 => "[x] Option 2",
 2 => "[ ] Option 3",
 3 => "[ ] Option 4",
 4 => "[x] Option 5",
 5 => "[ ] Option 6",
 6 => "[ ] Option 7"
);
$num_cols = 4;

//Use $i as a counter
$i = 0;
echo '<table>';
foreach ($array as $key => $val) {
    //If we are outputting the first column in a row, create a new tr tag
    if ($i % $num_cols == 0)
        echo '<tr>';

    //Output the column
    echo '<td>' . $val . '</td>';

    //If we are at the end of the number of columns, close the tr tag
    if ($i % $num_cols == 3)
        echo '</tr>';
    $i++;
}

//If we didn't close the tr tag in the loop, close it now
if ($i % $num_cols != 0)
    echo '</tr>';
echo '</table>';
?>

edited Oct 30, 2018 at 17:07

answered Oct 30, 2018 at 16:58

Mic1780

1,79410 silver badges23 bronze badges

7 Comments

Kishlin Over a year ago

Way too heavy for an easy problem. You should use existing php functions which are here to help you out, rather than trying to recreate what someone else already implemented. See the other answer with array_chunk.

Mic1780 Over a year ago

Yeah I could have use array_chunk but I came up with the proper solution without it. Just because I don't use a native function doesn't mean I should be downvoted...

Kishlin Over a year ago

This is not about not using native functions. Readability is at stake here. Your code is way harder to understand when the other solution is tacit in the glimpse of an eye.

myxaxa Over a year ago

i put a plus for you @Mic1780 ^_^ peace!

nocturns2 Over a year ago

I don't see anything wrong with this answer. It modifies the OP's code and yields the expected results that being sought. The comments are never bad (as long as they make sense). While I think both answers are good.

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