What I have is this:
const objArr = [
{name: "John", id: 1},
{name: "Marry", id: 2},
{name: "Jack", id: 3}
]
And I want this:
const names = [
"John",
"Marry",
"Jack"
]
How? Thanks!
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Have you made any attempt at all yourself yet?CertainPerformance– CertainPerformance2018-11-19 11:15:00 +00:00Commented Nov 19, 2018 at 11:15
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Clearly he asked question without even trying himselfsiddhant sankhe– siddhant sankhe2018-11-19 11:18:39 +00:00Commented Nov 19, 2018 at 11:18
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There's no need for that, I am fetching some objects from server, doing this for hours and lost my self... Actually the first answer is correct and I already tried that but did not realize that it work... No need for minuses, I am just tired... Thanks guysFatBoyGebajzla– FatBoyGebajzla2018-11-19 11:22:48 +00:00Commented Nov 19, 2018 at 11:22
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3 Answers
Use Array.prototype.map() to return only the name property.
The
map()method creates a new array with the results of calling a provided function on every element in the calling array.
const objArr = [
{name: "John", id: 1},
{name: "Marry", id: 2},
{name: "Jack", id: 3}
]
const names = objArr.map(p => p.name);
console.log(names);
1 Comment
trincot
You should really have voted to close as duplicate
here you go ;)
const names = objArr.map(person => person.name);
Comments
Just use map method in combination with destructuring by passing a callback provided function as argument.
const objArr = [{name: "John", id: 1}, {name: "Marry", id: 2}, {name: "Jack", id: 3}]
console.log(objArr.map(({name}) => name));
answered Nov 19, 2018 at 11:16
Mihai Alexandru-Ionut
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1 Comment
trincot
You should really have voted to close as duplicate