Passing model data to urlpatterns in Django's urls.py

Question

I am trying to write a generic urlpatterns entry in urls.py that would replace hardcoded entries, as below:

path('apple/', RedirectView.as_view(url='/apple/abc/'), name='apple_redirect'),
path('orange/', RedirectView.as_view(url='/orange/def/'), name='orange_redirect'),
path('banana/', RedirectView.as_view(url='/banana/ghi/'), name='banana_redirect'),

The model called fruits holds the following data:

    name = 'apple'
    url = 'apple/abc/'

    name = 'orange'
    url = '/orange/def/'

    name = 'banana'
    url = '/banana/ghi/'

I would like to avoid the need for manual addition of another path in case new entry in fruits model is added.

Yes having parameters in URLs of the normal thing to do and is well described in the tutorial and docs. Where are you having trouble? — Daniel Roseman
– Daniel Roseman, Commented Jan 7, 2019 at 21:46
well, I know how to capture URL parameters, say apple, but I do not know how to check if given parameter exists in fruits model, and if it does how to pull corresponding apple/abc and place it n the RedirectView.as_view(). I just started with django, hence potentially obvious things are not that clear yet... — Luke G
– Luke G, Commented Jan 7, 2019 at 21:54

Alex C · Accepted Answer · 2019-01-07 23:20:13Z

2

You should catch url param and pass it to your view like this

from django.shortcuts import redirect, get_object_or_404

def fruit_redirect_view(request, url_path):
    fruit = get_object_or_404(Fruit, name=url_path)
    return redirect(fruit.url)

So if fruit with such name exists, request will be redirected to fruit's url, otherwise 404 error will be raised

edited Jan 7, 2019 at 23:20

answered Jan 7, 2019 at 22:47

Alex C

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Luke G Over a year ago

Clear and easy to understand. Thank you!

Alasdair · Accepted Answer · 2019-01-07 23:07:22Z

1

If you want to use RedirectView, you can subclass it and override get_redirect_url.

class FruitRedirectView(RedirectView):
    def get_redirect_url(self):
        fruit = get_object_or_404(Fruit, name=self.kwargs['fruit'])
        return fruit.url

Then replace your individual fruit URL patterns with:

path('<slug:fruit>/', FruitRedirectView.as_view(), name='fruit_redirect'),

Note you don't need to use RedirectView here. Alex C's view is easier to understand, especially if you're not familiar with Django's generic views.

Note that once you have added the <slug:fruit>/, the view will raise a 404 error for any fruits that are not in the database. This is slightly different than when you had apple/ and orange/ in your URL patterns - in that case, Django might be able to match a pattern further down your list of URL patterns.

answered Jan 7, 2019 at 23:07

Alasdair

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1 Comment

Luke G Over a year ago

Thank you for detailed explanation.

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