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i have whole page in html and before output i want to replace all img src for data-src i am using 

  return (preg_replace('~<img[^>]*\K(?=src)~i','data-',$buffer));

but this doesnt match for example 

<img alt="alt" src="src">

it only matches when the src is first

<img src="src"

I cant get it to work like i want, can you help me edit this pattern to do what i need?

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  • 2
    Use html parser instead Commented Jan 8, 2019 at 13:10
  • i have to use regex Commented Jan 8, 2019 at 13:12
  • 1
    Why do you have to use regex? Homework? Commented Jan 8, 2019 at 13:14
  • yes i want to change src to data-src Commented Jan 8, 2019 at 13:25
  • 1
    @JiříKaštovský It works - regex101.com/r/mwvphb/1 Commented Jan 8, 2019 at 13:32

1 Answer 1

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2

I think this should work for you:

preg_replace("/(<img[^>]*)src=/", "$1data-src=", '<img alt="alt" src="src">');

$1 is a backreference representing the first matched group (everything in the parentheses of the pattern).

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1 Comment

it is only replace the first match,, how to replace in multiple tags?

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