Javascript Object get object by property

Question

I have an object of 2 users that looks like the following. The Object will only ever contain 2 users.

{
   "71":{
      "avatarURL":"__vue_devtool_undefined__",
      "createdAt":"2018-10-13T16:05:19Z",
      "customData":"__vue_devtool_undefined__",
      "id":"71",
      "name":"Angeline Fadel",
      "updatedAt":"2018-10-13T16:05:19Z",
      "presenceStore":{
         "71":"online"
      }
   },
   "199":{
      "avatarURL":"__vue_devtool_undefined__",
      "createdAt":"2018-10-13T16:06:13Z",
      "customData":"__vue_devtool_undefined__",
      "id":"199",
      "name":"Rodrigo Schuster",
      "updatedAt":"2018-10-13T16:06:13Z",
      "presenceStore":{
         "71":"online"
      }
   }
}

Let's say my user ID is 199, how to I get the name of the other user without knowing it's ID?

Please do not post image.....instead post code.

Mamun
– Mamun

2019-03-02 14:32:51 +00:00
Commented Mar 2, 2019 at 14:32 — Mamun
– Mamun, Commented Mar 2, 2019 at 14:32

rishat · Accepted Answer · 2019-03-02 14:39:04Z

1

With Object.keys, you can get an array of keys:

const users = { 199: {...}, 71: {...} };
const ids = Object.keys(users); // -> ['199', '71']

Knowing that the array will only contain two items and the "other" key, you might use Array.prototype.find to get the other item:

const myId = '199';
const targetId = ids.find(id => id !== myId); // -> '71'

Remember that object keys are always strings, so you may want to tweak the filtering and operations on IDs in a way that they are treated as (or coerced into) numbers.

answered Mar 2, 2019 at 14:39

rishat

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Comments

Anurag Awasthi · Accepted Answer · 2019-03-02 14:36:00Z

0

var obj={
  199: {
    name: "abc"
  },
  71: {
    name: "def"
  }
}

var knownKey = 199;
var otherKey = Object.keys(obj).filter(key => key != knownKey).pop();
console.log("name = " + obj[otherKey].name);

answered Mar 2, 2019 at 14:36

Anurag Awasthi

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Comments

Sebastian Speitel · Accepted Answer · 2019-03-02 14:40:01Z

0

You could get the ids using Object.keys() and filter them.

const usrs = {
  '1': {
    name: 'a'
  },
  '2': {
    name: 'b'
  }
};

function other(usrs, id) {
  const allId = Object.keys(usrs);
  console.log('allId:', allId);
  const otherId = allId.filter(k => k !== id);
  console.log('otherId:', otherId);
  const otherUser = otherId.map(uid => usrs[uid]);
  console.log('otherUser:', otherUser);
  const otherNames = otherUser.map(u => u.name);
  return otherNames
}

console.log(other(usrs, '1'));

answered Mar 2, 2019 at 14:40

Sebastian Speitel

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Comments

Maheer Ali · Accepted Answer · 2019-03-02 14:42:10Z

0

You can access the values using Object.keys to get ids. And then filter() to get other user

let users = {
  '71':{name:"First User"},
  '199':{name:"Second User"}
}
let id = '199'
let otherId = Object.keys(users).filter(key => key !== id)[0]
console.log(users[otherId].name);

edited Mar 2, 2019 at 14:42

answered Mar 2, 2019 at 14:34

Maheer Ali

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2 Comments

itsliamoco Over a year ago

But what it the order of the users in the object change?

Maheer Ali Over a year ago

@itsliamoco sorry I think i misunderstood. I updated

jaredrethman · Accepted Answer · 2019-03-02 15:08:06Z

You could use delete

const users = {
   "71":{
      "avatarURL":"__vue_devtool_undefined__",
      "createdAt":"2018-10-13T16:05:19Z",
      "customData":"__vue_devtool_undefined__",
      "id":"71",
      "name":"Angeline Fadel",
      "updatedAt":"2018-10-13T16:05:19Z",
      "presenceStore":{
         "71":"online"
      }
   },
   "199":{
      "avatarURL":"__vue_devtool_undefined__",
      "createdAt":"2018-10-13T16:06:13Z",
      "customData":"__vue_devtool_undefined__",
      "id":"199",
      "name":"Rodrigo Schuster",
      "updatedAt":"2018-10-13T16:06:13Z",
      "presenceStore":{
         "71":"online"
      }
   }
};

const knowUserId = '199';
const knowUserIndex = Object.keys(users).indexOf(knowUserId);

if(knowUserIndex > -1){
	delete users[knowUserId]; 
}

console.log(users)

Sunil Chaudhary · Accepted Answer · 2019-03-02 15:53:10Z

0

You can achieve it by following code. Suppose obj is the object and id variable stores the id. Now, use Object.keys to get the keys (which is array) and filter out the result based on !== id. Use otherId to get the relevant object and name.

obj = {
   "71":{
      "avatarURL":"__vue_devtool_undefined__",
      "createdAt":"2018-10-13T16:05:19Z",
      "customData":"__vue_devtool_undefined__",
      "id":"71",
      "name":"Angeline Fadel",
      "updatedAt":"2018-10-13T16:05:19Z",
      "presenceStore":{
         "71":"online"
      }
   },
   "199":{
      "avatarURL":"__vue_devtool_undefined__",
      "createdAt":"2018-10-13T16:06:13Z",
      "customData":"__vue_devtool_undefined__",
      "id":"199",
      "name":"Rodrigo Schuster",
      "updatedAt":"2018-10-13T16:06:13Z",
      "presenceStore":{
         "71":"online"
      }
   }
}
id = "199"
otherId = Object.keys(obj).find(data => data !== id)
result = obj[otherId].name
alert(result)

edited Mar 2, 2019 at 15:53

answered Mar 2, 2019 at 14:39

Sunil Chaudhary

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1 Comment

adiga Over a year ago

Note that otherId is an array: [ "71" ] and not 71. It works probably because [ "71" ].toString() is 71. You should use find instead

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