How to find the exact class by CSS Selector in selenium python?

Question

I want to get all class named = "panel-content" only, so i have done this:

driver.find_elements_by_css_selector("div.panel-content")

but it also selects the class named = "accordion-table panel-content", as it has "panel-content" string in it's name. but what i want is only "panel-content" class.how to do that?

Can you show us what the html looks like? You'll have to find a unique selector. In the firefox devtools you can right-click -> copy -> css selector to copy the exact css selector for an element, maybe this helps. — Lorenz Henk
– Lorenz Henk, Commented Mar 26, 2019 at 12:49
Can you explain that further? If some element has the raw class string accordion-table panel-content, that means that this element has both the class accordion-table and panel-content — Nico Haase
– Nico Haase, Commented Mar 26, 2019 at 12:55

Infern0 · Accepted Answer · 2019-03-26 11:50:53Z

2

https://www.w3schools.com/cssref/css_selectors.asp

Here you go:

CSS selector:

[class='panel-content']

Locator:

driver.find_elements_by_css_selector("[class='panel-content']")

answered Mar 26, 2019 at 11:50

Infern0

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2 Comments

JeffC Over a year ago

This is not a good way or a CSS-like way to do this. You have basically reduced the class name check to a string match. If any other class gets added to this element, this will fail.

Infern0 Over a year ago

By request he wanted "all class named = "panel-content""

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