display div inside php using echo

Question

I want display my button if it have isset($_GET). I am trying to do like this.

<?php if(isset($_GET['project_id'])){
                echo '<div class="add_btn_primary"> <a href="manage_project_users.php?project_id=<?php echo $_GET['project_id'];?>">Project Users</a> </div>';
                }?>

its giving me error like

 Parse error: syntax error, unexpected 'project_id' (T_STRING), expecting ',' or ';' in C:\xamppp\htdocs\mayank\add_project.php on line 101

I am not getting idea what I should do for echo project_id in div. Let me know if someone can help me for that. Thanks

I typically find that errors looking for , or ; are found before the line flagged in the error call. We would need more of your code to find it, but look at your lines carefully first. If you have a color coded editor, you may find a clue in improperly colored lines. — elbrant
– elbrant, Commented Mar 31, 2019 at 18:13

Ankur Choudhury · Accepted Answer · 2019-03-31 17:23:14Z

1

Thats incorrect to use echo inside another echo and how can you start a new php tag without closing the first. The correct way is to concatenate the variable along the string passed in echo, here is how

<?php if(isset($_GET['project_id'])){
            echo '<div class="add_btn_primary"> <a href="manage_project_users.php?project_id='.$_GET['project_id'].'">Project Users</a> </div>';
            }?>

instead of breaking the php tags break the ' quotes to concatenate the value in the string.

answered Mar 31, 2019 at 17:23

Ankur Choudhury

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lifeisbeautiful · Accepted Answer · 2019-03-31 17:13:16Z

1

Why do you need again tag inside echo just use it as below:

<?php 

if(isset($_GET['project_id']))
{
  echo ('<div class="add_btn_primary"><a href="manage_project_users.php?project_id='.$_GET["project_id"].'>Project Users</a></div>');
}
?>

answered Mar 31, 2019 at 17:13

lifeisbeautiful

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