PHP/HTML echo a variable in a div

Question

I have a div which works fine

  <div id="fb-root"></div>
   <fb:like href="<?php echo $link; ?>" send="true" width="450" show_faces="true" font=""> 
   </fb:like>

If I try to use an echo, I don't get the value of $link when I do this.

echo '<div id="fb-root"></div>
<fb:like href="<?php echo $link; ?>" send="true" width="450" show_faces="true" font="">
</fb:like>';

likewise this one too. i cannot get the $link.

echo '<iframe src="http://www.facebook.com/plugins/like.php?app_id=208015255907895&amp;href="',$link,'"&amp;send=true&amp;layout=button_count&amp;width=50&amp;show_faces=true&amp;action=like&amp;colorscheme=light&amp;font=trebuchet+ms&amp;height=21" scrolling="no" frameborder="0" style="border:none; overflow:hidden; width:50px; height:21px;" allowTransparency="true"></iframe> '

Any help?

pls see the $link with the answer from @fender echo '<iframe src="facebook.com/plugins/…" scrolling="no" frameborder="0" style="border:none; overflow:hidden; width:50px; height:21px;" allowTransparency="true"></iframe> ' — karto
– karto, Commented Jul 27, 2011 at 12:50

Yoshi · Accepted Answer · 2011-07-27 11:34:06Z

3

You can't use <?php ... ?> in an echo. Try:

echo '<div id="fb-root"></div><fb:like href="', $link, '" send="true" width="450" show_faces="true" font=""></fb:like>';

answered Jul 27, 2011 at 11:34

Yoshi

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8 Comments

Fender Over a year ago

shouldn't it be echo '<div id="fb-root"></div><fb:like href="'. $link. '" send="true" width="450" show_faces="true" font=""></fb:like>'; . instead of ,

KingCrunch Over a year ago

@Fender: , works too (remember, that echo is a language construct and not a function). The difference: echo $a,$b; is like echo $a; echo $b; and . is the common concatenation. ideone.com/hDbwq or ideone.com/89iww : Note, that in the first example the string `"Hello object:" is returned, but in the second one is not.

Matěj G. Over a year ago

@Fender It doesn't matter in case of echo

Yoshi Over a year ago

@Fender Try echo 'foo', 1 + 2, 'bar'; echo 'foo' . 1 + 2 . 'bar'; and you'll see why I tend to use , with echo. :)

Fender Over a year ago

oh yea... you are right. Never thought of it this way ;-) You never stop learning :-)

|

genesis · Accepted Answer · 2011-07-27 11:35:02Z

0

echo '<div id="fb-root"></div><fb:like href="'.$link.'" send="true" width="450" show_faces="true" font=""></fb:like>';

you cannot add <?php ?> brackets into your echo

answered Jul 27, 2011 at 11:35

genesis

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Comments

Eskil Mjelva Saatvedt · Accepted Answer · 2011-07-27 11:35:19Z

0

you are messing up ' " and a new php tag

echo '<div id="fb-root"></div>
<fb:like href="'. $link .'" send="true" width="450" show_faces="true" font="">
</fb:like>';

answered Jul 27, 2011 at 11:35

Eskil Mjelva Saatvedt

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Comments

Lawrence Cherone · Accepted Answer · 2011-07-27 11:35:26Z

0

Try This:

echo '<div id="fb-root"></div>
 <fb:like href="'.$link.'" send="true" width="450" show_faces="true" font="">
 </fb:like>';

answered Jul 27, 2011 at 11:35

Lawrence Cherone

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1 Comment

karto Over a year ago

see this too. $link seems not to work '<iframe src="facebook.com/plugins/…" scrolling="no" frameborder="0" style="border:none; overflow:hidden; width:50px; height:21px;" allowTransparency="true"></iframe> '

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