how to get part of string by regular expression in python

Question

I want to get part of string by regular expression I try this but it returns more than I need. This my code :

Release_name = 'My Kitchen Rules S10E35 720p HDTV x264-ORENJI'
def get_rls(t):
    w = re.match(".*\d ", t)

    if not w: raise Exception("Error For Regular Expression")
    return w.group(0)


regular_case = [Release_name]
for w in regular_case:
    Regular_part = get_rls(w)
    print(">>>> Regular Part: ", Regular_part)

This code for this example " My Kitchen Rules S10E35 720p HDTV x264-ORENJI " return this "My Kitchen Rules S10E35 " but i do not need the "S10E35" just return this My Kitchen Rules

Wiktor Stribiżew · Accepted Answer · 2019-03-31 20:31:12Z

4

You may use

w = re.match(r"(.*?)\s+S\d+E\d+", t)

and since the value you need is in Group 1:

return w.group(1)

See the Python demo, output is >>>> Regular Part: My Kitchen Rules.

Pattern details

(.*?) - any 0+ chars other than line break chars, as few as possible
\s+ - 1+ whitespaces
S\d+E\d+ - S char, 1+ digits, E and 1+ digits

The re.match will only start matching from the start of the string, ^ at the start of the pattern is not necessary.

answered Mar 31, 2019 at 20:31

Wiktor Stribiżew

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