Retrieve only a part of a string in python

Question

I have a path string something like '/foo/bar1/bar2/test.txt'. I want to retrieve just '/foo/bar1/' from the string and want to ignore the rest. I tried doing that with \/([\w\s]+)\/|,(?!\w)+? but that didn't help.

Can someone help me with this ?

Thanks in advance

What is special with /foo/bar1/? For regex, there must be a strict indicator for selecting the right part. Or for eumiro's answer, change in the number of / or changing the string might resolve a wrong answer.. What do you really try to do here?... — Mp0int
– Mp0int, Commented Mar 28, 2012 at 7:52

eumiro · Accepted Answer · 2012-03-28 07:38:53Z

2

s = '/foo/bar1/bar2/test.txt'

'/'.join(s.split('/')[:3])

# returns '/foo/bar1'

Change that 3 to the appropriate number. For further path manipulation have a look at os.path methods.

answered Mar 28, 2012 at 7:38

eumiro

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2 Comments

Sumedh Sidhaye Over a year ago

thanks eumiro :) ... regex is not always the best solution i guess

Li-aung Yip Over a year ago

In general, when working with file paths you nearly always want to use either plain string methods (like split) or the os.path methods, which are robust across operating systems and file path conventions.

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