Imagine something like:
const newItem = ['item 1', 'item 0', 'item 1', 'item 2', 'item 1', 'item 0'];
If I want to remove all 'item 1' I can use:
for (let i = newItem.length-1; i--;){
if (newItem[i] === "item 1") newItem.splice(i, 1);
}
The question is if I have an array inside another array how can I do?
const newItem = [
['item 1', 'item 0', 'item 1'],
['item 2', 'item 1', 'item 0']
];
Thanks!
You can use map and filter.map will return a new array and inside the callback check if the item which is ['item 1', 'item 0', 'item 1'] &
['item 2', 'item 1', 'item 0'] includes item 1
const newItem = [
['item 1', 'item 0', 'item 1'],
['item 2', 'item 1', 'item 0']
];
let k = newItem.map(function(item) {
return item.filter(elm => elm !== 'item 1')
});
console.log(k)
//newItem is not changed
console.log(newItem)
item.includes ? (Aside from reducing the number of loops)
newItem is not changed. You actually need to remove value from that arraymap is used. You can even run the snippet to see it work.newItem is not changed. We expect that array to get changed with no item1map to newItem.You can use a combination of map and filter:
const newItem = [
['item 1', 'item 0', 'item 1'],
['item 2', 'item 1', 'item 0']
];
console.log(newItem.map(a => a.filter(e => e !== 'item 1')));Just use nested forEach() loop:
const newItem = [
['item 1', 'item 0', 'item 1'],
['item 2', 'item 1', 'item 0']
];
newItem.forEach((innerArray) => {
innerArray.forEach((innerItem, i) => {
if (innerItem === "item 1") innerArray.splice(i, 1);
});
});
console.log(newItem);
If you know which index you want to access, one way to easily access this:
var arr = [[1,2,3], [5,6,7]];
console.log(arr[0][1]); // This will print 2, the second element of the first array item.
You can also easily iterate the nested array items using nested loop:
var arr = [
["item1", "item2", "item3"], ["item1", "item2", "item3"]];
arr.forEach(function(arrayItem){
arrayItem.forEach(function(item, index, array){
if(item === "item1"){
array.splice(index, 1); // Removes the matching item from the arrayItem.
}
});
});
arr = arr.map(subArr => subArr.filter(element => element !== 'item 1'))fororforEach()