How do I change the values of an multidimension array in JavaScript?

Question

I'm trying to solve this problem, I have already tried some things that I know of but it doesn't work. I believe it's the if statement that I'm not doing right. Can somebody give me a light?

var numbers = [
  [ 1,2,3],
  [ 4,5,6],
  [ 7,8,9]];

for(var row = 0; row < numbers.length; row++){
    for(var column = 0; column < numbers[row].length; column++){
        if(numbers[row].length % 2 === 0){
            numbers[row][column] = "even";
        }else{
            numbers[row][column] = "odd";
        }
        console.log(numbers[row][column]);
    }
}

I expect the array numbers have the elements changed for "even" and "odd".

In your modulus, don't you want if(numbers[row][column] %2 === 0)? — Chris White
– Chris White, Commented Apr 19, 2019 at 21:18

junvar · Accepted Answer · 2019-04-19 21:19:16Z

1

Your predicate numbers[row].length % 2 === 0 is checking if the row has an even number of elements. I assume what you want is numbers[row][column] % 2 === 0.

answered Apr 19, 2019 at 21:19

junvar

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1 Comment

Adria Vieira Over a year ago

I knew it I was doing the If statement wrong. Thank you.

Jarek Kulikowski · Accepted Answer · 2019-04-19 21:19:26Z

0

Is this what you are looking for?

var numbers = [
  [ 1,2,3],
  [ 4,5,6],
  [ 7,8,9]];

for(var row = 0; row < numbers.length; row++){
    for(var column = 0; column < numbers[row].length; column++){
    
        console.log(numbers[row][column]  %2 === 0 ? 'even' : 'odd');
    }
}

answered Apr 19, 2019 at 21:19

Jarek Kulikowski

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Comments

Francesco · Accepted Answer · 2019-04-19 21:19:47Z

0

If you want the result array to look something like this

[
   ["odd", "even", "odd"],
   etc...
]

Then your if statement is missing the column argument

if(numbers[row][column] % 2 === 0){

answered Apr 19, 2019 at 21:19

Francesco

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Comments

AttemptedMastery · Accepted Answer · 2019-04-19 21:21:26Z

0

var numbers = [
  [ 1,2,3],
  [ 4,5,6],
  [ 7,8,9]
];


 for (let i = 0; i < numbers.length; i++){
    for(let j = 0; j < numbers[i].length; j++){
        if (numbers[i][j] % 2 !== 0) {
            numbers[i][j] = "odd"
        } else{
            numbers[i][j] = 'even'
        }
    }
 }

In your conditional, you are asking if the length of the element is divisible by 2, when it should be the element itself. Remember, you are already in your nested loop at that point of your algorithm, so you are displaying only the numbers inside the nested arrays and not the arrays themselves.

answered Apr 19, 2019 at 21:21

AttemptedMastery

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1 Comment

Adria Vieira Over a year ago

Thank you for that. I didn't know.

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