How do I find out if my user's input is a number?
input = raw_input()
if input = "NUMBER":
do this
else:
do this
What is "NUMBER" in this case?
Add a comment
|
4 Answers
Depends on what you mean by "number". If any floating point number is fine, you can use
s = raw_input()
try:
x = float(s)
except ValueError:
# no number
else:
# number
1 Comment
Alexei Sholik
If you want to also support complex numbers, use
complex(). For simple ints int() should suffice.If you're testing for integers you can use the isdigit function:
x = "0042"
x.isdigit()
True
2 Comments
Alexei Sholik
Sadly enough,
x = "0.5"; x.isdigit() == False. Not suitable for floats.string = raw_input('please enter a number:')
Checking if a character is a digit is easy once you realize that characters are just ASCII code numbers. The character '0' is ASCII code 48 and the character '9' is ASCII code 57. '1'-'8' are in between. So you can check if a particular character is a digit by writing:
validNumber=False
while not validNumber:
string = raw_input('please enter a number:')
i=0
validNumber=True
while i
if not (string[i]>='0' and string[i]<='9'):
validNumber=False
print 'You entered an invalid number. Please try again'
break
i=i+1
Comments
An answer I found elsewhere on StackOverflow [I forget where] gave the following code for checking if something was a number:
#This checks to see if input is a number
def is_number(s):
try:
float(s)
return True
except ValueError:
return False
