PHP, loop through dynamic array by count

Question

So I am working on a JQuery Step Form. It is being populated with dynamic information from the database. I have a particular list of items that is 21 items in the array. I would like to break these down into groups of 5 or 6 per step, so the form isn't so long.

I know I could use array_slice for example, but since this list is dynamic, I don't know how many there will always be. It will kind of be paginated in a sense but I don't need pagination links and such. Just a way to return 5 items, then 5 items and if the last iteration only has 2 items then that is it.

So for example:

$array = ( 
  array(
    "name" => "Peter Parker",
    "alterego" => "Spiderman",
  ),
  array(
    "name" => "Clark Kent",
    "alterego" => "Superman",
  ), 
  array(
    "name" => "Bruce Wayne",
    "alterego" => "Batman",
  ),
);

And then I want to break this down to only list 2 items per group.

Yes @Andreas, this is correct. I mentioned you in the answer below. — RiotAct
– RiotAct, Commented May 27, 2019 at 3:34

Nick · Accepted Answer · 2019-05-27 03:10:28Z

1

You can use array_chunk for example:

$chunks = array_chunk($array, 5);
foreach ($chunks as $chunk) {
    // display form for these 5 values
}

answered May 27, 2019 at 3:10

Nick

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Comments

Emma Marcier · Accepted Answer · 2019-05-27 03:31:10Z

0

Andreas' initial advice is great. Maybe here, we might want to design some callback functions based on the pagination sizes that we wish to have:

array_slice($array, getChunkStart($array), getChunkLength($array));

or if we just look for a specific column size:

array_chunk($array, sizeof(array_column($array, "column_key")));

edited May 27, 2019 at 3:31

answered May 27, 2019 at 3:21

Emma Marcier

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