REGEX input validation

you can try the following regex:

"([\w-]+)\/([\w-]+)"

Edit: regex explained:

• ([\w-]+) in the square brackets we say we want to match \w: matches any word character (equal to [a-zA-Z0-9_]). After this, we have "-", which just adds literally the symbol "-" to the matching symbols.
• "+" says we want one or more symbols from the previous block: [\w-]
• \/ matches the symbol "/" directly. It should be escaped in the regex, that's why it is preceded by "\"
• ([\w-]+) exactly like point 1, matches the same thing since the two parts are identical.
• () - those brackets mark capturing group, which you can later use in your code to get the value it surrounds and matches. Example:

Full match: 1X-/-XX

Group 1: 1X-

Group 2: -XX

Here is a demo with the matching cases - click. If this doesn't do the trick, let me know in the comments.

This will do the job:

"[-\w]+/[-\w]+"(?:,"[-\w]+/[-\w]+")*

Explanation:

"           # quote
[-\w]+      # 1 or more hyphen or word character [a-zA-0-9_]
/           # a slash
[-\w]+      # 1 or more hyphen or word character [a-zA-0-9_]
"           # quote
(?:         # non capture group
  ,         # a comma
  "         # quote
  [-\w]+    # 1 or more hyphen or word character [a-zA-0-9_]
  /         # a slash
  [-\w]+    # 1 or more hyphen or word character [a-zA-0-9_]
  "         # quote
)*          # end group, may appear 0 or more times

Demo

Here, we would be starting with a simple expression with quantifiers:

("[A-Za-z0-9_-]+\/[A-Za-z0-9_-]+")(,|$)

where we collect our desired three chars in a char class, followed by slash and at the end we would add an optional ,.

Demo

RegEx Circuit

jex.im visualizes regular expressions: