convert and format string to an array of characters in swift

Question

how do I convert this string to an array of characters ignoring the first 2 characters and line breaks (\n) or spaces ? so I do have this:

var leds = """
1 1
XXX
000
00X
"""

to return this to me as a result:

['x','x','x','0','0','0','0','0','x']

I have this, but it doesn't ignore the spaces, line breaks or the number of the first line:

let characters = Array(leds)
print(characters)

thank you very much in advance

Martin R · Accepted Answer · 2019-06-20 11:01:13Z

5

Split the string into an array of lines, and drop the first line. Then use flatMap to map each line to an array of characters and concatenate the result.

let array = leds.components(separatedBy: .newlines)
    .dropFirst()
    .flatMap(Array.init)

print(array) // ["X", "X", "X", "0", "0", "0", "0", "0", "X"]

With map instead of flatMap you would get a “nested array” corresponding to the rows and columns from the input string:

let board = leds.components(separatedBy: .newlines)
    .dropFirst()
    .map(Array.init)

print(board) // [["X", "X", "X"], ["0", "0", "0"], ["0", "0", "X"]]

edited Jun 20, 2019 at 11:01

answered Jun 20, 2019 at 9:41

Martin R

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Comments

Anupam Mishra · Accepted Answer · 2019-06-20 10:18:23Z

0

This could also be useful-

if let firstLine = leds.components(separatedBy: CharacterSet.newlines).first {
        let removeFirstLineStr = leds.replacingOccurrences(of: firstLine, with: "")
        let characters = String(removeFirstLineStr.filter { !" \n\t\r".contains($0) })
        print(Array(characters))
    }

OR

func getCharacters() {
    guard let firstLineStr = leds.components(separatedBy: "\n").first else {
        return
    }
    let removeFirstLineStr = leds.replacingOccurrences(of: firstLineStr, with: "")
    let characters = String(removeFirstLineStr.filter { !" \n\t\r".contains($0) })
    print(Array(characters))
}

answered Jun 20, 2019 at 10:18

Anupam Mishra

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1 Comment

JL GallardoV Over a year ago

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