I have a list of values in which some values are words separated by commas, but are considered single strings as shown:
l = ["a",
"b,c",
"d,e,f"]
#end result should be
#new_list = ['a','b','c','d','e','f']
I want to split those strings and was wondering if there's a one liner or something short to do such a mutation. So far what, I was thinking of just iterating through l and .split(',')-ing all the elements then merging, but that seems like it would take a while to run.
import itertools
new_list = list(itertools.chain(*[x.split(',') for x in l]))
print(new_list)
>>> ['a', 'b', 'c', 'd', 'e', 'f']
Kind of unusual but you could join all your elements with , and then split them:
l = ["a",
"b,c",
"d,e,f"]
newList = ','.join(l).split(',')
print(newList)
Output:
['a', 'b', 'c', 'd', 'e', 'f']
Here's a one-liner using a (nested) list comprehension:
new_list = [item for csv in l for item in csv.split(',')]
See it run here.
Not exactly a one-liner, but 2 lines:
>>> l = ["a",
"b,c",
"d,e,f"]
>>> ll =[]
>>> [ll.extend(x.split(',')) for x in l]
[None, None, None]
>>> ll
['a', 'b', 'c', 'd', 'e', 'f']
The accumulator needs to be created separately since x.split(',') can not be unpacked inside a comprehension.
