Passing an input parameter in JS showing Unexpected end of input

Question

I am trying to pull a string variable into my javascript function from a PHP file and am being returned: Uncaught SyntaxError: Unexpected end of input.

I have tried to use onclick="showContent('home')" but this does not load the page at all. I assumed that placing home in parentheses would act as a string parameter and fill that variable in the javascript function.

In my header.php: echo "<img src='../images/home.png' onclick='showContent('home')' alt='Home' /></a>";

In my menu.js:

function showContent(showThis){ alert(showThis); }

Possible duplicate of "Notice: Undefined variable", "Notice: Undefined index", and "Notice: Undefined offset" using PHP — aynber
– aynber, Commented Oct 15, 2019 at 19:19
Double-check where you have $home defined, it's not able to use the variable. — aynber
– aynber, Commented Oct 15, 2019 at 19:29
@PatrickQ No, it still does. The header.php file is where the html is being generated from. — Frank Doe
– Frank Doe, Commented Oct 15, 2019 at 20:00

kaczmen · Accepted Answer · 2019-10-15 19:27:48Z

0

Try like this:

echo "<img src='../images/home.png' onclick='showContent(\"$home\")' alt='Home' />";

answered Oct 15, 2019 at 19:27

kaczmen

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3 Comments

Frank Doe Over a year ago

This shows up as empty. And when I click view source code it appears like this in the final HTML: onclick='showContent("")'

Patrick Q Over a year ago

@FrankDoe Then $home is empty. You should include (in your question) the code that is supposed to be assigning a value to $home

Frank Doe Over a year ago

Updated my question. My apologies.

MD.Tabish Mahfuz · Accepted Answer · 2019-10-15 19:31:03Z

0

Try this. You are not interpolating the variable $home correctly into the JS.

echo "<img src=\"../images/home.png\" onclick=\"showContent('{$home}')\" alt=\"Home\" />";

answered Oct 15, 2019 at 19:31

MD.Tabish Mahfuz

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