Flutter Dart: RegEx to extract URLs from a String

Question

This is my string:

    window.urlVideo = 'https://node34.vidstreamcdn.com/hls/5d59908aea5aa101a054dec2a1cd3aff/5d59908aea5aa101a054dec2a1cd3aff.playlist.m3u8';
var playerInstance = jwplayer("myVideo");
var countplayer = 1;
var countcheck = 0;
playerInstance.setup({
    sources: [{
        "file": urlVideo
    }],
    tracks: [{
        file: "https://cache.cdnfile.info/images/13f9ddcaf2d83d846056ec44b0f1366d/12.vtt",
        kind: "thumbnails"
    }],
    image: "https://cache.cdnfile.info/images/13f9ddcaf2d83d846056ec44b0f1366d/12_cover.jpg",
});

function changeLink() {
    window.location = "//vidstreaming.io/load.php?id=MTM0OTgz&title=Mairimashita%21+Iruma-kun+Episode+12";
}
window.shouldChangeLink = function () {
    window.location = "//vidstreaming.io/load.php?id=MTM0OTgz&title=Mairimashita%21+Iruma-kun+Episode+12";
}

I am using flutter dart.

How can I get window.urlVideo URL link and image URL link and .vtt file link?

Or

How can I get a list of URLs from a String? I tried finding a way with and without using RegEx but I couldn't.

Any help is apreciated

You say you are using Flutter/Dart but the code you shared is Javascript. — J. S.
– J. S., Commented Dec 22, 2019 at 14:14
@JoãoSoares That is not the code. It is the value of the string. I want to scrape the urls from this string. — dheeraj reddy
– dheeraj reddy, Commented Dec 22, 2019 at 14:29
So your string is all this javascript code and you want to extract 3 URLs from it? Are you scrapping a web page? Surely there is a better way for you to obtain these urls without having to do this from your Flutter App. — J. S.
– J. S., Commented Dec 22, 2019 at 14:45

Blasanka · Accepted Answer · 2019-12-22 14:49:12Z

41

This may not be the complete regex, but this worked for me for randomly picked links:

void main() {
  final text = """My website url: https://blasanka.github.io/
Google search using: www.google.com, social media is facebook.com, http://example.com/method?param=flutter
stackoverflow.com is my greatest website. DartPad share: https://github.com/dart-lang/dart-pad/wiki/Sharing-Guide see this example and edit it here https://dartpad.dev/3d547fa15849f9794b7dbb8627499b00""";

  RegExp exp = new RegExp(r'(?:(?:https?|ftp):\/\/)?[\w/\-?=%.]+\.[\w/\-?=%.]+');
  Iterable<RegExpMatch> matches = exp.allMatches(text);

  matches.forEach((match) {
    print(text.substring(match.start, match.end));
  });
}

Result:

https://blasanka.github.io/
www.google.com
facebook.com
http://example.com/method?param=flutter
stackoverflow.com
https://github.com/dart-lang/dart-pad/wiki/Sharing-Guide
https://dartpad.dev/3d547fa15849f9794b7dbb8627499b00

Play with it here: https://dartpad.dev/3d547fa15849f9794b7dbb8627499b00

answered Dec 22, 2019 at 14:49

Blasanka

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6 Comments

CHRIS LEE Over a year ago

This should be marked as the correct answer!

Kamlesh Over a year ago

I have a String Made by https://cretezy.com and Expected output: Made by <a href="https://cretezy.com">https://cretezy.com</a>. Kindly suggest me how can we do this? Thanks a lot.

Kamlesh Over a year ago

Not worked for me. I have a string which has https://support.google.com/firebase?authuser=0#topic=6399725 url and your solution converts it to like https://support.google.com/firebase?authuser=0 ignoring hash and further text string #topic=6399725. Kindly suggest how can we solve it. Thanks a lot.

Blasanka Over a year ago

@Kamlesh you can add any special char you want to the reg expression as mentioned in above comments. Based on the special char you may have to use escape character

ÄR Âmmãř Żąîñh Over a year ago

It also extract multi dots also. like goo... this.is

|

Crazy Lazy Cat · Accepted Answer · 2019-12-22 15:52:50Z

11

Try this,

final urlRegExp = new RegExp(
    r"((https?:www\.)|(https?:\/\/)|(www\.))[-a-zA-Z0-9@:%._\+~#=]{1,256}\.[a-zA-Z0-9]{1,6}(\/[-a-zA-Z0-9()@:%_\+.~#?&\/=]*)?");
final urlMatches = urlRegExp.allMatches(text);
List<String> urls = urlMatches.map(
        (urlMatch) => text.substring(urlMatch.start, urlMatch.end))
    .toList();
urls.forEach((x) => print(x));

answered Dec 22, 2019 at 15:52

Crazy Lazy Cat

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1 Comment

Kamlesh Over a year ago

Thank you so much dear, your solution worked for me perfectly :)

user229044 · Accepted Answer · 2020-01-06 02:28:24Z

7

Getting just the https? and ftp url's that are in quotes is this :

r"([\"'])\s*((?:(?:https?|ftp):\/\/)(?:\S+(?::\S*)?@)?(?:(?:(?:[1-9]\d?|1\d\d|2[01]\d|22[0-3])(?:\.(?:1?\d{1,2}|2[0-4]\d|25[0-5])){2}(?:\.(?:[1-9]\d?|1\d\d|2[0-4]\d|25[0-4]))|(?:(?:[a-zA-Z0-9\u00a1-\uffff]+-?)*[a-zA-Z0-9\u00a1-\uffff]+)(?:\.(?:[a-zA-Z0-9\u00a1-\uffff]+-?)*[a-zA-Z0-9\u00a1-\uffff]+)*(?:\.(?:[a-zA-Z\u00a1-\uffff]{2,})))|localhost)(?::\d{2,5})?(?:\/(?:(?!\1|\s)[\S\s])*)?)\s*\1"

Where the Url is captured in group 2.

https://regex101.com/r/UPmLBl/1

edited Jan 6, 2020 at 2:28

user229044♦

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answered Dec 22, 2019 at 18:54

user12097764

Comments

E. Sun · Accepted Answer · 2020-08-28 19:40:49Z

6

Much safer to use a library like linkify instead of rolling your own regex.

/// Attempts to extract link from a string.
///
/// If no link is found, then return null.
String extractLink(String input) {
  var elements = linkify(input,
      options: LinkifyOptions(
        humanize: false,
      ));
  for (var e in elements) {
    if (e is LinkableElement) {
      return e.url;
    }
  }
  return null;
}

answered Aug 28, 2020 at 19:40

E. Sun

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1 Comment

Her0Her0 Over a year ago

Linkify uses the following regex right now: r'^(.*?)((?:https?:\/\/|www\.)[^\s/$.?#].[^\s]*)'. Based on my testing at https://regexr.com/3e6m0, this matches https://google..............totallyrealurl,ofcourse!?

Tatsuya Fujisaki · Accepted Answer · 2024-08-30 09:29:23Z

Blasanka's answer does not work for me because it recognizes "..." as a URL.

Instead, the following works for me ...

/// Implements https://stackoverflow.com/a/6041965.
Iterable<String> getUrls(String input) => RegExp(
      r'(http|ftp|https):\/\/([\w_-]+(?:(?:\.[\w_-]+)+))([\w.,@?^=%&:\/~+#-]*[\w@?^=%&\/~+#-])',
    ).allMatches(input).map((match) => match.group(0)).nonNulls;

... and for the original poster's text.

void main() {
  getUrls(input).forEach(print);
}

// Text from the original poster
const input = '''
window.urlVideo = 'https://node34.vidstreamcdn.com/hls/5d59908aea5aa101a054dec2a1cd3aff/5d59908aea5aa101a054dec2a1cd3aff.playlist.m3u8';
var playerInstance = jwplayer("myVideo");
var countplayer = 1;
var countcheck = 0;
playerInstance.setup({
    sources: [{
        "file": urlVideo
    }],
    tracks: [{
        file: "https://cache.cdnfile.info/images/13f9ddcaf2d83d846056ec44b0f1366d/12.vtt",
        kind: "thumbnails"
    }],
    image: "https://cache.cdnfile.info/images/13f9ddcaf2d83d846056ec44b0f1366d/12_cover.jpg",
});

function changeLink() {
    window.location = "//vidstreaming.io/load.php?id=MTM0OTgz&title=Mairimashita%21+Iruma-kun+Episode+12";
}
window.shouldChangeLink = function () {
    window.location = "//vidstreaming.io/load.php?id=MTM0OTgz&title=Mairimashita%21+Iruma-kun+Episode+12";
}
''';

Result

https://node34.vidstreamcdn.com/hls/5d59908aea5aa101a054dec2a1cd3aff/5d59908aea5aa101a054dec2a1cd3aff.playlist.m3u8
https://cache.cdnfile.info/images/13f9ddcaf2d83d846056ec44b0f1366d/12.vtt
https://cache.cdnfile.info/images/13f9ddcaf2d83d846056ec44b0f1366d/12_cover.jpg

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