Flutter/ Parsing a part of url

Question

So basically I have a QR code generator in the app, I already implemented a feature generating it with url, such as domain.com/userid?=111. So, now I want QR code scanner to scan it and get only the id part of the user out of it, like it scanned the url example provided above, and then I just want to get '111' part to process. How can I implement it?

Shouldn't your url be domain.com?userid=111 instead of domain.com/userid?=111 — JideGuru
– JideGuru, Commented Jun 24, 2020 at 12:38
@JideGuru, no it should be domain.com/?userid=111, read more here: stackoverflow.com/a/1617074/1204153 — Andy
– Andy, Commented Jun 24, 2020 at 14:53
Ignore my comment, both should work and I don't want to start a debate about it like on that thread :) Either way, we can both agree OP's URI is wrong. — Andy
– Andy, Commented Jun 24, 2020 at 14:55

JideGuru · Accepted Answer · 2020-06-24 15:07:37Z

2

Use Uri queryParametersAll:

Uri url = Uri.parse('https://www.example.com/?userid=111');
print(url.queryParametersAll['userid'][0]);

answered Jun 24, 2020 at 15:07

JideGuru

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Ketan Ramteke · Accepted Answer · 2020-06-24 12:35:14Z

0

You can use substring method to get the part of it.

// Dart 2.6.1 

main() {
  String str = "domain.com/userid?=111";
  print(str.substring(str.indexOf("=")+1));
}

answered Jun 24, 2020 at 12:35

Ketan Ramteke

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