Get value from jsonelement's jsonarray with Java and Gson

Question

I have this code:

try {
    URL url = new URL("My api url");
    HttpURLConnection connection = (HttpURLConnection) url.openConnection();
    connection.addRequestProperty("User-Agent", "MyUserAgent");

    InputStream inputStream = connection.getInputStream();
    InputStreamReader reader = new InputStreamReader(inputStream);

    JsonElement element = new JsonParser().parse(reader);

    System.out.println(element);
} catch (IOException e) {
    e.printStackTrace();
}

My api response:

[
  {
    "id": 12345,
    "name": "1.0"
  }
]

I need to get the name parameter as a string, but I don't know how to do it.

Ok, what did you mean by I need to get the name parameter as a string, but I don't know how to do it — Youcef LAIDANI
– Youcef LAIDANI, Commented Feb 14, 2020 at 15:26

Youcef LAIDANI · Accepted Answer · 2020-02-14 15:35:49Z

1

I think you are looking for :

JsonElement name = element.getAsJsonArray().get(0).getAsJsonObject().get("name");

Output

"1.0"

Or to get the value of name :

String name = element.getAsJsonArray().get(0).getAsJsonObject().get("name").getAsString();

Output

1.0

answered Feb 14, 2020 at 15:35

Youcef LAIDANI

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8 Comments

alex3025 Over a year ago

If I need to compare the name value (version) to another, how I can do?

Youcef LAIDANI Over a year ago

@alex3025 can you clarify your question more or by an example, I don't get you well

alex3025 Over a year ago

I want to exec code if the version that I get with name is greater than another string: "1.0.1"

Youcef LAIDANI Over a year ago

@alex3025 this can be as another question, but I will give you a clue, you can add zeros to the end of the string which are low than your max version length, then remove the dots, and then convert the two strings to Integer and compare this two integers, for example in your case "1.0" -> "1.0.0" so you have "1.0.0" and "1.0.1" then -> "100" "101" then your action if (Integer.valueOf("100") > Integer.valueOf("101")), as I said, If you don't understand my solution, you can post a question and I will try to answer you step by step

alex3025 Over a year ago

I'm going to try what you write in the comment

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