What is the correct syntax to detect an empty 2 Dimensional array in PHP? I have attempted to do so myself using the functions "isset()" and "!empty()" for both "2dArray[0]" and "2dArray[0][0]", but even with an empty array the result comes back positive. Here is a snippet of code from one of the times where I tried this:
if(isset($strengths[0][0]) || isset($sizes[0][0]))
{
print_r($strengths[0][0]);
echo "<br>blah<br>";
print_r($sizes[0][0]);
}
Yet the arrays are both empty. Using print_r we can even see that the arrays return nothing. Here is a picture example of a different attempt using isset(2dArray[0]):
In the picture you can see the array is also empty again.
It's important to note that I can use 2dArray[1] perfectly; it detects that there there is no second row as expected, but that means I cannot have any instances where there is only 1 row in either 2D array because it is positioned at position 0 with nothing at position 1 to be detected anyway.
What am I doing wrong?
Edit 1: The code:
var_dump($strengths[0][0]);
var_dump($sizes[0][0]);
returns:
array(0) { }
array(0) { }
and the code:
var_dump($strengths[0]);
var_dump($sizes[0]);
returns:
array(1) { [0]=> array(0) { } }
array(1) { [0]=> array(0) { } }
Edit 2: This is my init:
$sizes[][] = array();
This is where data is set:
foreach($products as $product)
{
//product information
foreach($mods as $mod)
{
//mod information
//when array is empty $mods is empty
if ($modType == "SIZE")
{
$sizes[$si][0] = $modValue . $modValueSuffix;
$sizes[$si][1] = $modPrice;
$sizes[$si][2] = $modID;
$si++;
$strengthOrSize = true;
}
}
}
I believe I should have done $sizes[] = array(); for a 2D array. I overlooked this because it's such a short piece of code I did not give it much attention.

var_dumpand paste it.