bash script to run jupyter notebook in virtualenv

Question

To speed up launching projects I created a small bash script which does the following:

takes an argument (project name)
moves to the directory of that project
starts a virtual environment
starts a jupyter notebook

#!/bin/bash

if [ "$1" == "k3" ]; then
    project_path="tau-code/k3-analysis/"
fi

codepath="/media/peter/somedrive/code"
full_path="$codepath/$project_path"

# Go to directory of project
cd $full_path

# Start environment & notebook if available
pipenv shell
jupyter notebook --ip=0.0.0.0

It activates the environment, but does not run the jupyter command. When I exit the environment I see the error:

line 16: jupyter: command not found

I can manually type jupyter notebook --ip=0.0.0.0 in my newly created environment and that does work.

What may be the problem?

can manally you check which jupyter in newly created environment ? and manually run env in newly created environment ? also same in your bash script after - pipenv shell pipenv shell env jupyter notebook --ip=0.0.0.0 i somewhere think its a path issue.. — mandar
– mandar, Commented Apr 20, 2020 at 7:43

Leon · Accepted Answer · 2020-04-13 17:42:43Z

4

+50

pipenv shell starts a new shell which must be deactivated by using exit. In your script any commands following the call to pipenv shell are not executed in that new shell. Instead they are executed in the same bash shell after the virtual environment shell is closed. You should use pipenv run jupyter notebook --ip=0.0.0.0

See pipenv documentation:

shell will spawn a shell with the virtualenv activated. This shell can be deactivated by using exit.

run will run a given command from the virtualenv, with any arguments forwarded (e.g. $ pipenv run python or $ pipenv run pip freeze).

answered Apr 13, 2020 at 17:42

Leon

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Comments

Gautam Ramachandra · Accepted Answer · 2020-04-20 14:52:21Z

1

Hi you need to add this

pipenv run jupyter notebook

answered Apr 20, 2020 at 14:52

Gautam Ramachandra

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