for loop with dynamic if statement in python

Question

I have these two list group_name and group_ids_list im looping these two list and I want to do an if condition based on the group id of this list. I want to know if there is a way to do this if groupId == 0: dynamically because this current example wont scale very well if I keep adding more groups and so on.

group_name = ['a','a','b','c', 'a', 'd']
group_ids_list = [0,0,1,2,0,3]
for groupName, groupId in itertools.zip_longest(group_name, group_ids_list):
    if groupId == 0:
        print('found group 0 name is {}'.format(groupName))
    elif groupId == 1:
        print('found group 1 name is {}'.format(groupName))
    elif groupId == 2:
        print('found group 2 name is {}'.format(groupName))

Is group_ids really supposed to be the indexes or is it supposed to be the values found in group_ids_list? — Mark
– Mark, Commented Apr 15, 2020 at 4:17
I updated my code im actually looping two list and yes group id is associated to an id. if you see the group_name it coresponds to some value like a if in group 0 or b if in group 1 and so on. — Max Powers
– Max Powers, Commented Apr 15, 2020 at 4:22
it looks like you changed the question a lot since I answered so I deleted my answer. — David Erickson
– David Erickson, Commented Apr 15, 2020 at 4:28

mohammed wazeem · Accepted Answer · 2020-04-15 04:31:39Z

1

If you want to just print the group id and name. You can use string formatting to achieve this.

group_names = ['a','a','b','c', 'a', 'd']
group_ids = [0, 0, 1, 2, 0, 3]
for group_name, group_id in zip(group_names, group_ids):
    print('found group {} with name {}'.format(group_id, group_name))

edited Apr 15, 2020 at 4:31

answered Apr 15, 2020 at 4:26

mohammed wazeem

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