Getting File name from String in Shell Script

Question

I need to get the name of the file (IN_INK_GOOGLE_20200519.dat) in below string . I want to do it using shellscript. Also, as filename regex conditions are - should start with IN_INK & end with .dat and if it matches more than once, only one match or first match should print. is it possible? ,

echo "-sIN.GOOGLE.IN.INK.INNK.INACC\n-i/am/ft/data/INK/out/GOOGLE_INK/INK/out/IN_INK_GOOGLE_20200519.dat\n-o/apps/tnk/in/download/in/IN_INK_GOOGLE_20200519.dat\n-uinnko1\n-end"

Gilbert · Accepted Answer · 2020-05-22 11:25:28Z

1

One solution is to pipe into sed as follows:

echo ... | sed -e 's/[.]dat.*/.dat/' -e 's|.*/||'

To use a "pure shell" solution try the # and % features of variable expansions:

e="-sIN.GOOGLE.IN.INK.INNK.INACC\n-i/am/ft/data/INK/out/GOOGLE_INK/INK/out/IN_INK_GOOGLE_20200519.dat\n-o/apps/tnk/in/download/in/IN_INK_GOOGLE_20200519.dat\n-uinnko1\n-end" 

f="${e%%.dat*}.dat";  #strip trailing clutter after first

echo ${f##*/};    #echo just name
echo IN_INK${f##*/IN_INK}  #variation

edited May 22, 2020 at 11:25

answered May 22, 2020 at 11:17

Gilbert

3,80619 silver badges21 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Getting File name from String in Shell Script

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related