How to parse the file name string from a file path in shell script?

Question

I have files in directory 'new_kb'. I want to iterate on each file and execute a c++ binary on the file, like below:

kb_dir=./new_kb
for entry in "$kb_dir"/*
do
  echo "$entry"
   $file_name  = parse(entry)
  ./build "$file_name"/"$file_name".txt 
  done

One example of 'entry' is:

./new_kb/peopleObj.txt

from the variable path 'entry', I need to parse the string below out:

'peopleObj'

How to do this in a shell script?

dan · Accepted Answer · 2022-02-12 11:05:57Z

2

Using shell built in parameter expansion:

file_name=${entry##*/}
file_name=${file_name%.txt}

Using basename(1):

file_name=$(basename "$entry" .txt)

Note that whitespace is fundamental to how shell commands are parsed, and all variable declarations should have no whitespace around =.

edited Feb 12, 2022 at 11:05

answered Feb 12, 2022 at 5:52

dan

5,4219 silver badges17 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

David C. Rankin Over a year ago

Worth noting that the parameter expansions are shell built-ins and avoid spawning a subshell that basename (from Linux coreutils) will require. This can provide substantial efficiency benefits if called within a loop (orders or magnitude depending on the number of iterations).

Daniel A. White · Accepted Answer · 2022-02-12 02:35:29Z

0

Use basename

$file_name=$(basename $entry .txt)

edited Feb 12, 2022 at 2:35

answered Feb 12, 2022 at 1:49

Daniel A. White

192k49 gold badges389 silver badges473 bronze badges

1 Comment

marlon Over a year ago

Error: build.sh: line 5: =peopleObject: command not found

Collectives™ on Stack Overflow

How to parse the file name string from a file path in shell script?

2 Answers 2

1 Comment

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

1 Comment

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related