Regex match giturl with optional file name

Question

I need to get two parts (username/gistid and filename) from a github gist url.

Sofar i got this:

  const gisturl = "https://gist.github.com/vanaf1979/329abed564c2ba10eda29a53b399ac69#file-parse-wp-rest-api-1-parse-js";
  const myRegexp = /\.com\/+(.*)?#file-(.*)/gi;
  const matches = myRegexp.exec(gisturl);
  console.log(matches);

whithc gives me

0: ".com/vanaf1979/329abed564c2ba10eda29a53b399ac69#file-parse-wp-rest-api-1-parse-js"
1: "vanaf1979/329abed564c2ba10eda29a53b399ac69"
2: "parse-wp-rest-api-1-parse-js"

So far so good, except the filename (#file-parse-wp-rest-api-1-parse-js) is optional and if i remove it from the string the regex doest match anymore.

So i need the regex to match both case with or without the filename.

Any help would be very appreciated.

The fourth bird · Accepted Answer · 2020-05-26 10:35:29Z

2

You could change the first part to use a negated character class instead [^#]+ matching any char except a #

Then you can make the second part optional and keep the capturing group for the part that comes after file-

Note that you can omit the plus sign after the forward slash \/+

\.com\/([^#]+)(?:#file-(.*))?

Regex demo

answered May 26, 2020 at 10:35

The fourth bird

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1 Comment

VA79 Over a year ago

That works like a charm! Thanks, Also for the explenation! You rock! :p

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