How to get matched array object based on their values in javascript

Question

I would like to know how to get the array object based on values in javascript. I have array object obj1, obj2 , how to get the object if name of obj1 matches with obj2 values in javascript

var obj1=[
  {name: "country", value: "countries"},
  {name: "city", value: "cities"}
]
var obj2=[
  {countries:"countries"},
  {sample: "sample"}
]
var result = this.getMatchedObj(obj1, obj2);

function getMatchedObj(obj){
    const newlist = obj1.map((elem) => obj2.find(e=>Object.values(e)===elem.value));
    return newlist;
}

Expected Output:

[
 {name: "country", value: "countries"}
]

Ajai · Accepted Answer · 2020-06-02 12:03:38Z

1

   var obj1=[
  {name: "country", value: "countries"},
  {name: "city", value: "cities"}
]
var obj2=[
  {countries:"countries"},
  {sample: "sample"}
]
let data = obj1.filter(ele=>obj2.findIndex(el=> Object.values(el)[0] ==ele.value)!=-1)
console.log(data);

answered Jun 2, 2020 at 12:03

Ajai

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Comments

MorKadosh · Accepted Answer · 2020-06-02 06:54:40Z

0

If I understood you correctly, this should work:

var obj1=[
  {name: "country", value: "countries"},
  {name: "city", value: "cities"}
]
var obj2=[
  {countries:"countries"},
  {sample: "sample"}
]

function getMatchedObj(obj1, obj2){
    const values = obj2.reduce((acc, cur) => acc.concat(Object.values(cur)),[]);
    const newlist = obj1.filter(({value}) => values.includes(value));
    return newlist;
}
const result = getMatchedObj(obj1, obj2);
console.log(result);

Here's a playground:

https://stackblitz.com/edit/js-6tmjcc

answered Jun 2, 2020 at 6:54

MorKadosh

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Comments

Tân · Accepted Answer · 2020-06-02 07:04:30Z

You can can with this:

var obj1=[
  {name: "country", value: "countries"},
  {name: "city", value: "cities"}
];
var obj2=[
  {countries:"countries"},
  {sample: "sample"}
];

var item = obj1.find(item => obj2.map(x => Object.values(x)[0]).indexOf(item.value) > -1);

console.log(item);

Get all of the object property values from obj2 to an array. Then making an array to check existing with obj1

Or using for loop:

var obj1=[
  {name: "country", value: "countries"},
  {name: "city", value: "cities"}
];
var obj2=[
  {countries:"countries"},
  {sample: "sample"}
];

for (var obj of obj2) {
  var values = Object.values(obj);
  
  var item = obj1.find(item => values.indexOf(item.value) > -1);
  
  if (item) {
    console.log(item);
  }
}

Siva Kondapi Venkata · Accepted Answer · 2020-06-02 07:24:16Z

0

Use filter, find and includes methods. If you just need one object, Then change filter call to find.

const getMatchedObj = (obj1, obj2) =>
  obj1.filter(({ value }) =>
    obj2.find((obj) => Object.values(obj).includes(value))
  );

var obj1 = [
  { name: "country", value: "countries" },
  { name: "city", value: "cities" },
];
var obj2 = [{ countries: "countries" }, { sample: "sample" }];

console.log(getMatchedObj(obj1, obj2));

answered Jun 2, 2020 at 7:24

Siva Kondapi Venkata

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