Starting a TCP client with python

Question

I'm learning ethical hacking with Python, and I have been trying to type a simple TCP client from BlackHat python book, but I have problems running the code I have written from the book.

import socket

target_host = "95.127.145.5"
target_post = 80

client = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
client.connect((target_host,target_post))

client = send("GET / HTTP/1.1\r\nHost: 95.127.145.5\r\n\r\n")

response = client.recv(4096)

I'm not sure if it's because it's python2 but if it is, I need advice on how to convert this code to python3 because my IDE is python 3.8.3 the error happens in ("GET / HTTP/1.1\r\nHost: 95.127.145.5\r\n\r\n") and I get the message "inspect type checker options". Any advice is highly appreciated.

check stackoverflow.com/questions/34192093/python-socket-get — Meroz
– Meroz, Commented Jun 2, 2020 at 20:37
I get the message "inspect type checker options" Is that all the output? — AMC
– AMC, Commented Jun 3, 2020 at 1:12

Roshin Raphel · Accepted Answer · 2020-06-02 20:26:18Z

1

You have to encode the text before sending the request,
This line is also wrong

client = send("GET / HTTP/1.1\r\nHost: 95.127.145.5\r\n\r\n")

It should be :

client.send("GET / HTTP/1.1\r\nHost: 95.127.145.5\r\n\r\n")

See :

import socket

target_host = "95.127.145.5"
target_post = 80

client = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
client.connect((target_host,target_post))

client.send("GET / HTTP/1.1\r\nHost: 95.127.145.5\r\n\r\n".encode())

response = client.recv(4096)

Also check whether the host is up or not

answered Jun 2, 2020 at 20:26

Roshin Raphel

2,7195 gold badges28 silver badges43 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

snaggingjoker45 Over a year ago

my bad there was a typo on that, i typed correctly just have problem on it sending on python3, but thank you your help is highly appreciated

Finlay McWalter · Accepted Answer · 2020-06-02 22:27:49Z

1

In python2,

client = send("GET / HTTP/1.1\r\nHost: 95.127.145.5\r\n\r\n")

should be

client.send("GET / HTTP/1.1\r\nHost: 95.127.145.5\r\n\r\n")

In python3, it just needs to be

client.send(b"GET / HTTP/1.1\r\nHost: 95.127.145.5\r\n\r\n")

edit: Roshin Raphel's answer does the encoding better than mine. And you're not using target_host when making up the request. So that line is probably better being

client.send(f"GET / HTTP/1.1\r\nHost: {target_host}\r\n\r\n".encode())

edited Jun 2, 2020 at 22:27

answered Jun 2, 2020 at 20:26

Finlay McWalter

1,3421 gold badge10 silver badges13 bronze badges

4 Comments

snaggingjoker45 Over a year ago

thank you so much for this answer, it is highly appreciated

snaggingjoker45 Over a year ago

i started getting this <built-in method recv of socket object at 0x006E2928>

Finlay McWalter Over a year ago

I think you may have done response=client.recv and not response=client.recv(4096)

snaggingjoker45 Over a year ago

thats a typo i made in there

Collectives™ on Stack Overflow

Starting a TCP client with python

2 Answers 2

1 Comment

4 Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

1 Comment

4 Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related