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So Im having trouble detecting rectangles that are embedded and overlapping as separate rectangles with python OpenCv

If given this image: These are rectangles embedded

or this image:

enter image description here

how do I detect these rectangles as 2 separate rectangles and not just one big polygon? and could you print the output onto the image?

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1 Answer 1

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Here is the code to identify the rectangles separately. The explanations are inline with the code:

import numpy as np
import cv2

# The standard stuff: image reading, grayscale conversion, blurring & edge detection
image = cv2.imread('rect_image.png')
orig = image.copy()
gray = cv2.cvtColor(image, cv2.COLOR_BGR2GRAY)
gray = cv2.GaussianBlur(gray, (3, 3), 0)
edges = cv2.Canny(gray, 50, 200)

# Finding and sorting contours based on contour area
cnts = cv2.findContours(edges, cv2.RETR_LIST, cv2.CHAIN_APPROX_SIMPLE)
cnts = cnts[0] if len(cnts) == 2 else cnts[1]
cnts = sorted(cnts, key = cv2.contourArea, reverse = True)[:6]

vertices = []
for i, c in enumerate(cnts):
    if i == 0:
        # This is the largest contour
        # For overlapping case the largest one will be the only one contour
        peri = cv2.arcLength(cnts[i], True)
        approx = cv2.approxPolyDP(cnts[i], 0.02 * peri, True)
        vertices.append(approx)
    elif i < len(cnts) - 1:
        # Searches for any other inner contour
        # Also filters out close contours generated due to thick line
        if not np.isclose(cv2.contourArea(cnts[i]), cv2.contourArea(cnts[i+1]), atol=20000):
            peri = cv2.arcLength(cnts[i+1], True)
            approx = cv2.approxPolyDP(cnts[i+1], 0.02 * peri, True)
            vertices.append(approx)

if len(vertices) == 1:
    # This case is where there is only one contour (the overlapping case)
    # There are eight extreme points for two overlapping rectangles
    # The distinct rectangles are colored in 'green' and 'red'
    extLeft1 = tuple(vertices[0][vertices[0][:, :, 0].argmin()][0])
    extRight1 = tuple(vertices[0][vertices[0][:, :, 0].argmax()][0])
    extTop1 = tuple(vertices[0][vertices[0][:, :, 1].argmin()][0])
    extBot1 = tuple(vertices[0][vertices[0][:, :, 1].argmax()][0])
    mask = np.isin(vertices[0][:, :, 1], (extRight1, extLeft1, extTop1, extBot1))
    indices = np.where(mask)
    vertices = np.delete(vertices[0], indices, 0)
    extLeft2 = tuple(vertices[vertices[:, :, 0].argmin()][0])
    extRight2 = tuple(vertices[vertices[:, :, 0].argmax()][0])
    extTop2 = tuple(vertices[vertices[:, :, 1].argmin()][0])
    extBot2 = tuple(vertices[vertices[:, :, 1].argmax()][0])

    x, y, w, h = cv2.boundingRect(np.array([extLeft1, extLeft2, extRight1, extRight2]))
    cv2.rectangle(image, (x, y), (x + w, y + h), (0, 255, 0), 2)
    x, y, w, h = cv2.boundingRect(np.array([extTop1, extTop2, extBot1, extBot2]))
    cv2.rectangle(image, (x, y), (x + w, y + h), (0, 0, 255), 2)
else:
    # This case is where there are inner rectangle (the embedded case)
    # The distinct rectangles are colored in 'green' and 'red'
    x, y, w, h = cv2.boundingRect(vertices[0])
    cv2.rectangle(image, (x, y), (x + w, y + h), (0, 255, 0), 2)
    x, y, w, h = cv2.boundingRect(vertices[1])
    cv2.rectangle(image, (x, y), (x + w, y + h), (0, 0, 255), 2)

# Displaying the images with identified colored rectangles
cv2.imshow("Input", orig)
cv2.imshow("Contour", image)
cv2.waitKey(0)
cv2.destroyAllWindows()

Below are the output of the detected rectangles drawn on the image in green and red colors:

enter image description here

enter image description here

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2 Comments

Thank you! and also in the embedded rectangles picture, lets say instead of one rectangle embedded there were multiple rectangles within the larger rectangle how would that be detected?
It's the same approach, you just need to iterate through the contours in a loop. I have kept those in two distinct lines of code to color them differently.

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